If a/3=b/4=c/7,then a+b+c/c is equal to …

a/3 = b/4 =c/7 =a+b+c/c =? so, use a/k1=b/k2=c/k3 which is a=k1 ;b=k2 ;c=k3 substitute a=3 ; b=4 ; c=7 a=b=c/c = 3+4+7/7= 14/7 =2

Ans. Given :  {tex}{a\over 3}={b\over 4}={c\over 7}{/tex}

So, 
{tex}=> {a\over 3} ={c\over 7}{/tex} 

{tex}=> {a\over c} ={3\over 7}{/tex} ..... (1)

Also, 
{tex}=> {b\over 4}={c\over 7}{/tex}

=> {tex}{b\over c}={4\over 7}{/tex}

Now, {tex}{a+b+c\over c} = {a\over c}+{b\over c}+{c\over c}{/tex}

=> {tex} {a\over c}+{b\over c}+ 1{/tex} 
From (1) and (2)

{tex}=> {3\over 7 }+{4\over 7} + 1 = {3+4+7\over 7} {/tex}

=> {tex}{14\over 7 } = 2{/tex}