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1/x_ 1/x_2 =3

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1/x_ 1/x_2 =3
  • 1 answers

Kunal Nawariya 5 years, 3 months ago

1/x -1/x-2=3 Take Lcm X-2-X /x(x-2)=3 -2/x^2-2x =3 -2=3(x^2-2x) -2=3x^2-6x 0=3x^2-6x+2 Hera,a=3,b=-6,c=2 D=b^2-4ac=(-6)^2-4*3*2=36-24=12 Since D>0 So x= -b+-√D/2a= 6+-√12/2*3= 6+-√12/6=6+√12/6,6-√12/6
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