If x/a=y/b=z/c,prove that x2/a2+y2/b2+z2/c2=(x+y+z)3/(a+b+c)2
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Ram Kushwah 5 years, 3 months ago
The question must be like:
x3/a2 + y3/b2 + z3/c2=(x+y+z)3/(a+b+c)2
**************************************************************
Let x/a=y/b=z/c=k
then x=ak,y=bk,z=ck
Now RHS=(x+y+z)3/(a+b+c)2
=(ak+bk+ck)3/(a+b+c)2
=k3(a+b+c)3/(a+b+c)2
=k3(a+b+c)
=k3a+k3b+k3c
= (x/a)3*a + (y/b)3*b + (z/c)3*c
=RHS
=x3/a2 + y3/b2 + z3/c2
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