Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Amlesh Yadav 8 years, 6 months ago
- 1 answers
Posted by Ricky Ponting 8 years, 6 months ago
- 0 answers
Posted by Sonu Singh 8 years, 6 months ago
- 0 answers
Posted by Suhail Ali 8 years, 6 months ago
- 0 answers
Posted by Yogesh Mishra 8 years, 6 months ago
- 0 answers
Posted by Abhishek Kumar 8 years, 6 months ago
- 2 answers
Abhishek Kumar 8 years, 6 months ago
Posted by Abhishek Kumar 8 years, 6 months ago
- 0 answers
Posted by Tiya Kapoor 8 years, 6 months ago
- 1 answers
Posted by Vickey Gujjar 8 years, 6 months ago
- 1 answers
Posted by Tarun Kumar 8 years, 6 months ago
- 2 answers
Posted by Kunal Verma 8 years, 6 months ago
- 1 answers
Rashmi Bajpayee 8 years, 6 months ago
{tex}{{\tan {{80}^ \circ } + \tan {{55}^ \circ }} \over {1 - \tan {{80}^ \circ }.\tan {{55}^ \circ }}} = - 1{/tex}
=> {tex}\tan \left( {{{80}^ \circ } + {{55}^ \circ }} \right) = - 1{/tex}
=> {tex}\tan {135^ \circ } = - 1{/tex}
=> {tex}\tan \left( {{{90}^ \circ } + {{45}^ \circ }} \right) = - 1{/tex}
=> {tex} - \tan {45^ \circ } = - 1{/tex}
=> {tex}-1=-1{/tex}
Hence proved
Posted by Jitendra Singh 8 years, 6 months ago
- 1 answers
Posted by Rohit Sharma 8 years, 6 months ago
- 1 answers
Ashutosh Kumar 8 years, 6 months ago
Mirror can be define as a surface, typically of glass coated with a metal amalgam, which reflects a clear image.
Posted by Mansooe Mansoor 8 years, 6 months ago
- 0 answers
Posted by Dharmveer Sharma 8 years, 7 months ago
- 3 answers
Jyotiraditya Sharma 8 years, 7 months ago
The author wants to say that ravages of time spare none
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Aman Sahani 6 years, 1 month ago
2Thank You