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Naveen Sharma 8 years, 1 month ago
{tex}3x^2 + 5x - 8 = 0 \\ 3x^2+8x-3x-8 = 0 \\ x(3x+8)-1(3x+8) = 0 \\ (x-1)(3x+8) =0\\ x = 1 , {-8\over 3} {/tex}
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{tex}{1-tan x\over 1+tan x} \\ = {tan {\pi\over 4} - tan x\over 1 +tan x.tan {\pi\over 4}}\\ = tan ({{\pi\over 4} - x} ){/tex}
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