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Sia ? 3 years ago
| Parameter | Simple Interest | Compound Interest |
| Definition | Simple Interest can be defined as the sum paid back for using the borrowed money, over a fixed period of time. | Compound Interest can be defined as when the sum principal amount exceeds the due date for payment along with the rate of interest, for a period of time. |
| Formula | S.I. = (P × T × R) ⁄ 100 | C.I. = P(1+R⁄100)t − P |
| Return Amount | The return is much lesser when compared to Compound Interest. | The return is much higher. |
| Principal Amount | The principal amount is constant | The principal amount keeps on varying during the entire borrowing period |
| Growth | The growth remains quite uniform in this method. | The growth increases quite rapidly in this method. |
| Interest Charged | The interest charged on is for the principal amount. | The interest charged on it is for the principal and accumulated interest. |
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Arpit Airen 3 years, 7 months ago
I guess you want to find the Particular Solution of the equation {tex}x(x^2-1) {dx \over dy} = 1 \ at\ y =0, x=2{/tex}
{tex}It \ can \ be\ written \ as => x(x^2-1) dx = dy{/tex}
=> {tex}(x^3-x) dx =dy{/tex}
On Integrating both side
{tex}{x^4 \over 4 }- {x^2 \over 2} = y{/tex} + c ....................1
Put x=2 & y=0 in equation 1
c = 2
Now put value of c in 1
{tex}{x^4 \over 4 }- {x^2 \over 2} = y + 2{/tex}
This is the Particular Solution of given differential equation.
Equation 1 is the General Solution of given differential equation.
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Sia ? 3 years, 8 months ago
https://mycbseguide.com/dashboard/textbook/ch/1288/t/1/q/1/m/0/s/0
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