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Ask QuestionPosted by Vishnu Chaudhary 7 years, 5 months ago
- 1 answers
Posted by Reetu Kumari 7 years, 5 months ago
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Posted by Akshara Grover 7 years, 5 months ago
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Posted by Murlee Manohar 7 years, 5 months ago
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Posted by Tan Jaat 7 years, 6 months ago
- 3 answers
Naveen Sharma 7 years, 6 months ago
3x2+5x−8=03x2+8x−3x−8=0x(3x+8)−1(3x+8)=0(x−1)(3x+8)=0x=1,−83
Posted by Tan Jaat 7 years, 6 months ago
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Posted by Sabeel Siddiqui 7 years, 6 months ago
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Posted by Sahil Bhandari 7 years, 6 months ago
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Posted by Abhisek Jaiswal 7 years, 6 months ago
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Posted by Sanjay Singh 7 years, 7 months ago
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Posted by Smaty Nickke Singh 7 years, 7 months ago
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Payal Singh 7 years, 7 months ago
Given : x2+1x2=829
To find : x3−1x3
Solution:
We know,
(x−1x)2=x2+1x2−2
=>(x−1x)2=829−2
=>(x−1x)2=649
=>(x−1x)=83
Also,
=>(x3−1x3)=(x−1x)(x2+1x2+1)
=>(x3−1x3)=(83)(829+1)
=>(x3−1x3)=(83)(919)
=>(x3−1x3)=72827
Posted by Dheeraj Ojha 7 years, 7 months ago
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Posted by Abhishek Vishwakarma 7 years, 7 months ago
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Posted by Ricky Ponting 7 years, 7 months ago
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Kritika Trehan 7 years, 5 months ago
sin(A+B)=sin A cos B + cos A sin B
3Thank You