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Makhan Meena 1 year, 8 months ago

Chapter 2 solutions
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Saksham Sharma 1 year, 9 months ago

Hh
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Preeti Dabral 2 years ago

The Venn diagram for (AB)The shaded portion represents (AB)

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Manmohan Barmaiya 2 years, 3 months ago

G
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Preeti Dabral 2 years, 3 months ago

 Let y=f(x)=cosecxf(x+h)=cosec(x+h)dydt=limh0f(x+h)f(x)h=limh0cosec(x+h)cosecxh=limh01h[1sin(x+h)1sinx]=limh0sinxsin(x+h)hsinxsin(x+h)=limh02cos(2x+h2)sin(h2)hsinxsin(x+h)=limh0cos(x+hh)sinxsin(u+h)limh0sinh2h/2=1cosxsinxsinxlimz0sinzz[z=h2; Then, z0 when h0]=cosxsinxsinx1=cosxsinx1sinx=cosecx.cotxdydx=1csecxcotx

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Abhishek Namdev 2 years, 3 months ago

(x = 2x-1),(y+1 = -5) x = 1 , y = -6
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Preeti Dabral 2 years, 4 months ago

Here total number of digits = 10
Number of digits used (no digit is repeated) = 4
Since 0 cannot be filled in the fourth place, so number of permutations for fourth place = 9
Now the remaining three places can be filled with 9 digits.
 Number of permutations = 9P3
=9!6!=9×8×7×6!6!=504
Hence total number of permutations =9×504=4536

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1+2
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Nilesh Yadav 2 years, 2 months ago

3

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