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Preeti Dabral 1 year, 11 months ago
Here the given AP is : 21,18,15,--------
Here a=21 and d=18-21=-3,an=-81
{tex}\mathrm{We}\;\mathrm{know}\;\mathrm{that}\;{\mathrm a}_{\mathrm n}=\mathrm a+(\mathrm n-1)\mathrm d{/tex}
{tex}\Rightarrow{/tex} -81=21+(n-1)(-3)
{tex}\Rightarrow{/tex} -81=21-3n+3
3n = 81+21+3=105
So n = {tex}\frac{105}{3}{/tex} = 35
So, -81 is the 35th term of this AP
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Preeti Dabral 1 year, 11 months ago
2x2 - 7x + 3 = 0
Comparing quadratic equation 2x2 - 7x + 3 = 0 with general form ax2 + bx + c = 0, we get a = 2, b = -7 and c = 3
Putting these values in quadratic formula {tex}x = \frac { - b \pm \sqrt { b ^ { 2 } - 4 a } } { 2 a }{/tex}
{tex}x = \frac { 7 \pm \sqrt { ( - 7 ) ^ { 2 } - 4 ( 2 ) ( 3 ) } } { 2 \times 2 } \Rightarrow x = \frac { 7 \pm \sqrt { 9 - 24 } } { 4 }{/tex}
{tex}\Rightarrow x = \frac { 7 \pm 5 } { 4 }{/tex}
{tex}\Rightarrow x = \frac { 7 + 5 } { 4 } , \frac { 7 - 5 } { 4 }{/tex}
{tex}\Rightarrow{/tex} x =3, ½
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