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Ask QuestionPosted by Balkrishna Pandey 5 years, 10 months ago
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Posted by Hifazat Ali 5 years, 10 months ago
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Yogita Ingle 5 years, 10 months ago
Relative Density
- The relative density of a substance is the ratio of its density to that of water.
- Relative density is a ratio so it has no unit.
Density = mass/volume
Relative density = density of substance/density of water
Hifazat Ali 5 years, 10 months ago
Posted by Mr Hadi 5 years, 10 months ago
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Yogita Ingle 5 years, 10 months ago
Statement : There is one and only one circle passing through three given noncollinear points.
Given : AB and CD are two equal chords of the circle.
OM and ON are perpendiculars from the centre at the chords AB and CD.
To prove : OM = ON.
Construction : Join OA and OC.
Proof :
In ΔAOM and ΔCON,
OA = OC . (radii of the same circle)
MA = CN . (since OM and ON are perpendicular to the chords and it bisects the chord and AM = MB, CN = ND)
∠OMA = ∠ONC = 90°
ΔAOM ≅ ΔCON (R. H. S)
OM = ON (c. p. c. t.)
Equal chords of a circle are equidistant from the centre.
Posted by Roshni Gupta 5 years, 10 months ago
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Hifazat Ali 5 years, 10 months ago
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Abu Hamza 4 years, 8 months ago
Yogita Ingle 5 years, 10 months ago
7246.8 = 7000 + 200 + 40 + 6 + 8/10
= 7 × 103 + 2 × 102 + 4 × 101 + 6 × 100 + 8 × 10-1
Posted by Umesh Bariya 5 years, 10 months ago
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Lakshminarayana Lucky 5 years, 9 months ago
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Nandan S 5 years, 9 months ago
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Yogita Ingle 5 years, 10 months ago
The base equation for a circle centered at (h,k) with radius r is:
(x - h)2+ (y - k)2 = r2
If the points are concyclic, they all lie on the graph for the same circle.
Thus, all points are solutions to a single equation of the circle
WE can plug each point into the base equation, and obtain a system of equationd
FOR POINT (-2,10)
Equation 1: (-2 - h)2 + (10 - k)2 = r2
FOR POINT (1,11)
Equation 2: (1 - h)2+ (11 - k)2 = r2
FOR POINT (6,10)
Equation 3: (6 - h)2 + (10 - k)2 = r2
FOR POINT (9,7)
Equation 4: (9 - h)2 + (7 - k)2 = r2
From Equation 1 and 2 above, since they have 2 different expressions equivalent to r2, we can construct an equation involving variables x and h.
r2 = r2
(-2 - h)2 + (10 - k)2 = (1 - h)2 + (11 - k)2
(-2 - h)(-2 - h) + (10 - k)(10 - k) = (1 - h)(1 - h) + (11 - k)(11 - k)
(4 + 2h + 2h + h2) + (100 -10k - 10k + k2) = (1 - h - h + h2) + (121 - 11k - 11k + k2)
h2 + 4h + 4 + k2 - 20k + 100 = h2-2h + 1 + k2 -22k + 121
We can subtract h and k from both sides.
4h + 4 - 20k + 100 = -2h + 1 -22k + 122
4h -20k + 104 = -2h - 22k + 122
Move all h and k variables to the left ... move all constants to the right
6H + 2K = 18
SYSTEM EQUATION 1: 6h + 2k = 18
From equation 3 and 4 above, we go through the same process to obtain a second system equation.
r2 = r2
(6 - h)2 + (10 - k)2 = (9 - h)2 + (7 - k)2
(6 - h)(6 - h) + (10 - k)(10 - k) = (9 - h)(9 - h) + (7 - k)(7 - k)
36 - 6h - 6h + h2+ 100 - 10k - 10k + k2 = 81 - 9h - 9h + h2 + 49 = 7k - 7k + k2
h2 - 12h + 36 + k2 - 20k + 100 = h2 - 18h + 81 + k2- 14k + 49
Simplify, and subtract h2 and k2from both sides
-12h - 20k + 136 = -18h - 14k + 130
Move the h and k variables to the left, and the constants to the right
-12h + 18h - 20k + 14k = 130 - 136
6h - 6k = -6
SYSTEM EQUATION 1: 6h - 6k = -6
6h +2k = 18
6h - 6k = -6
Multiply the second equation by -1, we have ... -6h + 6k = 6
Adding the 2 equations, we have
6h + 2k = 18
-6h + 6k = 6
8k =24
k = 3
Using substitution of k=3 into equation 6h + 2k = 18,
6h + 2(3) = 18
6h + 6 = 18
6h = 12
h = 2
Now, use one of the points on the circle ... (1, 11) and (h,k) ... (2,3), to find the radius
(1 - 2)2 + (11 - 3)2 = r2
1 + 64 = r2
65 = r2
r = √65
Thus the equation of our circle is:
(x - 2)2 + (y - 3)2 = (√65)2
Posted by Raji Raji 5 years, 10 months ago
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Yogita Ingle 5 years, 10 months ago
Book keeping is stated as the recording of day-to-day business transactions in the books of accounts. It involves identification of transactions of financial nature, recording them in the books of accounts and classifying them into the ledger accounts.
Posted by Abhishek Pradhan 5 years, 10 months ago
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Yogita Ingle 5 years, 10 months ago
SI unit of magnetic field is tesla (T). So, one tesla is that magnetic field in which a charge of one coulomb moving with a velocity of 1 m/s perpendicular to the magnetic field experiences a force of one newton.
Posted by Vivek Kumar 5 years, 10 months ago
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Snehal Kumar 5 years, 5 months ago
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Sandeep Kumar 5 years, 10 months ago
Yogita Ingle 5 years, 10 months ago
Functional group:
An atom or a group of atoms present in the molecules, which determines the characteristics property of the organic compounds, is called the functional group
Posted by Vivek Kumar 5 years, 10 months ago
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Yogita Ingle 5 years, 10 months ago
Lens is an optical device which converges or diverges the rays of light before transmitting. A lens has similar shape to lentils and genus of lentil is called Lens, thus a lens got its name after the shape and name of genus of lentils. A lens is made by combining at least one part of sphere made of transparent material, generally glass.
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