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Ankit Srivastava 5 years, 9 months ago

Amount of energy required by electron to remove out from an isolated gaseous atom called electon affinity
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0.0001(N)=0.0001(M) Ka=1.8 ×10^-5 pKa= -log10Ka= -log10(1.8 × 10^-5) =4.74 PH=(1÷2)×4.74 - (1÷2)log (0.0001) =4.37
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Saravanan Studio 5 years, 8 months ago

Cation is smaller than its parent atom because it loses electron(s) from its outer valence shell and bears a positive symbol . Anion gains electro(s) in its outer most valance shell and bears a negative symbol so that the no of electrons in the atom will be increased which leads to the larger radii than their parent atom
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Md Shahbaz 5 years, 11 months ago

Bcz it has a vast space between thetwo nucleus
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Prajwal Paul 5 years, 9 months ago

Google it

Namaj Reja 6 years, 2 months ago

Class 11
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Kaira Khan 6 years, 3 months ago

Suppose... Hn O3...... First you find hn O3 molecular mass.... Then H= 1 + N= 14 + O= 48=63/1= 63
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Raushan Kumar 6 years, 4 months ago

25

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