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  • 1 answers

Ram Kushwah 5 years, 3 months ago

The question must be like:

x3/a2 + y3/b2 + z3/c2=(x+y+z)3/(a+b+c)2

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Let x/a=y/b=z/c=k

then x=ak,y=bk,z=ck 

Now RHS=(x+y+z)3/(a+b+c)2

=(ak+bk+ck)3/(a+b+c)2

=k3(a+b+c)3/(a+b+c)2

=k3(a+b+c)

=k3a+k3b+k3c

= (x/a)3*a + (y/b)3*b + (z/c)3*c

=RHS

=x3/a2 + y3/b2 + z3/c2

 

 

  • 1 answers

Ram Kushwah 5 years, 3 months ago

inclination=45

so m=tan 45=1

c=-1(given)

so equation y=mx+c

y=1*x-1

y=x-1

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Ram Kushwah 5 years, 3 months ago

Here height =50 m

base= 200m

tanθ=height/base=50/200=1/4=tan14

so angle of depression=90-14=76

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Ayush Kumar 3 years, 8 months ago

answers
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Abhishek Gari 6 years, 3 months ago

Yes
  • 2 answers

Anwit Kumar 6 years, 4 months ago

20

Anwit Kumar 6 years, 4 months ago

1+2+3+4+5+6+7 8+9+10÷

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