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Harshita Singh 4 years, 10 months ago

Please give me chapter 5 solutions
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Yogita Ingle 4 years, 11 months ago

Plese check question: if your question is  tan ø cot ø  = sin ø cosec ø, then following answer applied

LhS= tan ø cot ø

= sin ø/cos ø  × cos ø/sin ø

= 1

RHS = sin ø cosec ø

= 1/cosecø ×cosec ø

= 1

LHS = RHS

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Do char wale rekhik samikaran 3 point 5
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Subhit Kumar 5 years, 1 month ago

V gvtvyvtvyv
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Jaya Sree 5 years, 3 months ago

Sums
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Yogita Ingle 5 years, 3 months ago

Formula of curved surface area of cone = πrl 

Where r is radius and l is slant height

Since we are given slant height is 10 cm and base radius is 7cm

So, Curved surface area of cone = 3.14 × 25 ×7

                                                      = 549.5

Hence the curved surface area of cone is 549.5 cm square.

 

L
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K. Sanjana 4 years, 8 months ago

ax²+bx+c X²-2x+1 p+q=b=-2 P×q=a×c=1×1=1 (p,q)=(-1,-1) X²-2x+1 X²-1x-1x+1 X(x-1)-1(x-1) (X-1)(X-1) (X-1)=0 X=1 *X=1,1

Rajan Kumar Pasi 5 years, 3 months ago

you have to find the zeroes of the equation. Write a full question. use the "middle-term splitting" method or "hit and trial" method. The zeroes will be 1 and 1. the equation can be written as (x-1)^2 = 0
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Chandan Mondal 5 years, 2 months ago

(1 - cos^2thita)/sin^2thita =sin^2thita/sin^2thita =1(proved)
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Dinesh Kumar Yadav 5 years, 3 months ago

S.I = P(n.(n+1))*r/2*12*100 400*20*21*8.5/2*12*100 = 595rs Deposit in 1 month = 400 Deppsit in 20month = 400*20 = 8000rs Amount = S.I+deposit = 595+8000 = 8595rs ANSWER
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