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Analysis of career graph of a cricketer (batting average for a batsman and bowling average for a bowler). Conclude the best year of his career. It may be extended for other players also – tennis, badminton, athlete

Posted by Dhairya Sharma 5 months, 1 week ago

CBSE > Class 12 > Applied Maths

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X/(x-1)(x-2)(x-3)

Posted by Sayantika Mondal 5 months, 4 weeks ago

CBSE > Class 12 > Applied Maths

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What is the mean of the numbers obtained on throwing a die having written 1 on three faces, 2 on two faces and 5 on one face?

Posted by Shobha V 6 months ago

CBSE > Class 12 > Applied Maths

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Show that 3⁴⁶ =17⁴⁶(mod 7)

Posted by Sleeping Beauty Rasi 7 months ago

CBSE > Class 12 > Applied Maths

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Posted by Pranav Makkar 9 months, 1 week ago

CBSE > Class 12 > Applied Maths

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Yash Jain 9 months, 1 week ago

P(3) = 0.18

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Calculate the mathematical expectation of number of weeks taken by a student to apply ahead of a college’s application deadline

Posted by Abhay Verma 9 months, 2 weeks ago

CBSE > Class 12 > Applied Maths

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Integral by partial 2x^2+1/x^2-3x+1

Posted by Kajal Verma 1 year ago

CBSE > Class 12 > Applied Maths

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A group of 7 weeks old chickens reared on a high protein

Posted by Shalin8 B 1 year ago

CBSE > Class 12 > Applied Maths

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Case study of itnegrals

Posted by Shivam Khandelwal 1 year ago

CBSE > Class 12 > Applied Maths

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In the year 2000, Mr. Talwar took a home loan of ₹ 3000000 from the State Bank of India at 7.5% p.a. compounded monthly for 20 years. Based on the above information, answer the following questions:

Posted by Aman Kumar 1 year, 1 month ago

CBSE > Class 12 > Applied Maths

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Exercise 11.1

Posted by Shivansh Kanojia 1 year, 2 months ago

CBSE > Class 12 > Applied Maths

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X+1/X+2 ≥ 1 , then

Posted by Kalp Shrimal Jain 1 year, 2 months ago

CBSE > Class 12 > Applied Maths

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Find critical points of the following functions f x 50 x 0.5x 1000

Posted by Bhumi Goel 1 year, 3 months ago

CBSE > Class 12 > Applied Maths

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Case study of determants

Posted by Devansh Parihar 1 year, 3 months ago

CBSE > Class 12 > Applied Maths

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e^xy-axy=a

Posted by Nisarg Parmar 1 year, 5 months ago

CBSE > Class 12 > Applied Maths

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1100110 by 1001

Posted by Royal Baniye 1 year, 5 months ago

CBSE > Class 12 > Applied Maths

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Mahitesh Rawat 1 year, 5 months ago

Continuity ?

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Predicting the outcome of election -exit poll

Posted by Sanchita Shrivastava 3 months, 3 weeks ago

CBSE > Class 12 > Applied Maths

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Analysis of career graph of cricketer (batting average for batsmen and bolling average for boller )conclude the best year of his career

Posted by Sanchita Shrivastava 1 year, 6 months ago

CBSE > Class 12 > Applied Maths

1 answers

Ayushi Singh 1 year, 5 months ago

I want this

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Find the least non negative remainder when 3 power 50 is divided by 7

Posted by Vetali Mittal 1 year, 7 months ago

CBSE > Class 12 > Applied Maths

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If determinant of x+a p+c splits into Y+b q+d Exactly k determinats of order 2,each element of which contain one term,then the value of k is

Posted by Indhumathi.J Jambu 1 year, 7 months ago

CBSE > Class 12 > Applied Maths

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In year 2000 Mr. Talwar took a home loan of rs. 300000 from state Bank of India at 7.5

Posted by Aikansh Gupta 1 year, 9 months ago

CBSE > Class 12 > Applied Maths

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Tanushri Bhayani 1 year, 9 months ago

Kindly provide complete question !!

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A lady's bag contains 2 black and 1 red pens. One pen is drawn at random and then put back in the box after noting its colour. The process is repeated again. If X denotes the number of red pens recorded in the two draws. Describe X.

Posted by Rupa Josyula 1 year, 9 months ago

CBSE > Class 12 > Applied Maths

2 answers

Lakshya Sharma 1 year, 6 months ago

Tatti

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Pushkar Mahapale 1 year, 9 months ago

apne iska premium subscription like raha hai kya

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Find the amount to which ₹12,000 will accumulate at the effective rate of 3% for 10 years, 4% for 4 years and 5% for 2 years.

Posted by Tanushri Bhayani 1 year, 9 months ago

CBSE > Class 12 > Applied Maths

1 answers

Preeti Dabral 1 year, 9 months ago

The effective rate is the actual rate compounded annually. Therefore, the required sum S is given by
S = 12000 (1 + {tex}\frac{3}{100}{/tex})¹⁰ (1 + {tex}\frac{4}{100}{/tex})⁴ (1 + {tex}\frac{5}{100}{/tex})²
{tex}\Rightarrow{/tex} S = 12000 (1.03)¹⁰ (1.04)⁴ (1.05)²
{tex}\Rightarrow{/tex} S = 12000 (1.34391638) (1.16985856) (1.1025) = 20800.10
Hence, the amount is ₹20,800.10

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What amount should be deposited at the end of every 6 months to accumulate ₹ 50000 in 8 years, if money is worth 6% p.a. compounded semi-annually? (Given (1.03)16 = 1.6047)

Posted by Tanushri Bhayani 1 year, 9 months ago

CBSE > Class 12 > Applied Maths

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Preeti Dabral 1 year, 9 months ago

₹2480.57

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A rifleman is firing at a distant target and has only 10% chance of hitting it. The least number of rounds, he must fire in order to have more than 50% chance of hitting it at least once is

Posted by Tanushri Bhayani 1 year, 9 months ago

CBSE > Class 12 > Applied Maths

1 answers

Preeti Dabral 1 year, 9 months ago

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Can anyone let me know all the properties of matrix

Posted by Tanushri Bhayani 1 year, 9 months ago

CBSE > Class 12 > Applied Maths

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A is a square matrix such that A2 = A, then (I + A)3 - 7A is equal to

Posted by Tanushri Bhayani 1 year, 9 months ago

CBSE > Class 12 > Applied Maths

2 answers

Tanushri Bhayani 1 year, 9 months ago

Ohh' alright

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Nishant Dogra 1 year, 9 months ago

Using the properties of matrix algebra, we can expand the expression (I + A)3 as follows: (I + A)3 = (I + A)(I + A)(I + A) = (I + A)(I2 + 2IA + A2) = (I + A)(I + 2A + A) = I2 + 3IA + 3A2 + A3 = I + 3A + 3A2 + A3 (since A2 = A) Substituting this expression into the original equation, we get: (I + A)3 - 7A = (I + 3A + 3A2 + A3) - 7A = I + 2A + 3A2 - 7A = I - 5A + 3A2 Therefore, (I + A)3 - 7A is equal to I - 5A + 3A2.

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integrate (3e ^ x - 5e ^ (- x))/(4e ^ x + 5e ^ (- x)) dx

Posted by Bhumika Jain 1 year, 9 months ago

CBSE > Class 12 > Applied Maths

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9. If A = [[- i, 0], [0, i]], (i ^ 2 - 1) B = [[1, 0], [0, - 1]] and AB = a*l_{2} then a is equal to

Posted by Tanushri Bhayani 1 year, 9 months ago

CBSE > Class 12 > Applied Maths

2 answers

Tanushri Bhayani 1 year, 9 months ago

Hmm' got it 👍 thanks

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Nishant Dogra 1 year, 9 months ago

Solution We can calculate the product AB as follows: AB = [[-i, 0], [0, i]] [[1, 0], [0, -1]] = [[-i, 0], [0, -i]] Next, we can calculate the determinant of AB as follows: det(AB) = (-i) * (-i) - 0 * 0 (determinant of a 2x2 matrix) = 1 Now, we can use the formula for the product of determinants to find the determinant of A multiplied by the determinant of (i^2-1)B: det(A) * det((i^2-1)B) = det(AB) det(A) * (i^2-1)^2 * det(B) = 1 Substituting the known values, we get: det(A) * (i^2-1)^2 * (-1/1) = 1 det(A) * 4 = 1 det(A) = 1/4 Since A is a 2x2 matrix, its determinant can be calculated as follows: det(A) = (-i) * i - 0 * 0 (determinant of a 2x2 matrix) = -1 Therefore, we have a contradiction: det(A) = -1 and det(A) = 1/4. Hence, there is no value of a that satisfies the given conditions.

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Under the pure market competition scenario, the demand function 𝑝𝑑 and the supply function 𝑝𝑠 for a certain commodity are given as 𝑝𝑑 = 8 𝑥+1 − 2 and 𝑝𝑠 = 𝑥+3 2 respectively, where 𝑝 is the price and 𝑥 is the quantity of the commodity. Using integrals, find the producer’s surplus.

Posted by Tanushri Bhayani 1 year, 9 months ago

CBSE > Class 12 > Applied Maths