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  • 1 answers

Drashti Sanghvi 4 years, 4 months ago

solve equation by oxidation number method : p4 + no3^-1 gives po4^-3 + no2 oxidation no of p4 is 0, no3^-1 is 5, po4^-3 is 5 & no2 is 4 oxidation: p4 gives 4po4^-3 increases by 20 × 1 reduction :no3^-1 gives no2 decreases by 1 × 20 p4 gives 4po4^-3 20no3^-1 gives 20no2 p4 + 16h2o gives 4po4^-3 20no3^-1 gives 20no2 + 20h2o balanced equation is p4 + 20no3^-1 + 8h+ gives 4po4^-3 + 20no2 + 4h2o
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Yogita Ingle 4 years, 9 months ago

N2​O is more polar than CO2​. This is because CO2​ is linear and symmetrical. Its net dipole moment is zero (O=←C=→O).N2​O is linear but symmetrical. It is considered as a resonance hybrid of the following two structures
:N..=N+=O:..↔:N≡N+=..O:..​−​
It has a net dipole moment of 0.116D.

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Yogita Ingle 4 years, 9 months ago

 Due to the stable configuration, they do not accept an electron and hence they have large positive electron gain enthalpy.  

An electron has to enter the next higher principal quantum level which leads to a very unstable electronic configuration.

Dεερακ Ȿιηɠꜧ 4 years, 9 months ago

Noble Gases have a full filled orbital in their last shell, they have a very stable electronic configuration, they don't need any extra electron.
An electron has to enter the next higher principal quantum level which leads to a very unstable electronic configuration.
by taking electron thair energy will be increased, but all atom wants to live in their least energy state...<hr>
very short answer it is difficult to add an extra electron due to stable electronic configuration. so it needs energy to do so.
  • 4 answers

Dεερακ Ȿιηɠꜧ 4 years, 9 months ago

Oh! to app 6 baje soti ho , or 3 baje uthti ho ??

Dεερακ Ȿιηɠꜧ 4 years, 9 months ago

$$\textsf{Vese aap itna kyo jagti ho, this is not a good way to study }$$

Dεερακ Ȿιηɠꜧ 4 years, 9 months ago

$$\texttt{scroll to see, full }$$ $$\textfrak{*sp_{3} }$$

Dεερακ Ȿιηɠꜧ 4 years, 9 months ago

$$\mathfrak{Because\ 'p' \ subshell \ has\ only \ 3\ orbital\ which\ get\ completed \ in \sp-{3}\ hybridization\. }$$
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Dεερακ Ȿιηɠꜧ 4 years, 9 months ago

$$CH_{4(g)}+2O_{2(g)} \overset{\Delta}{\longrightarrow} CO_{2(g)} + 2 H_{2} O_{(l)}$$ ✓✓

Dεερακ Ȿιηɠꜧ 4 years, 9 months ago

$$CH_{4(s)} + O_{2(g)} \longmapsto CO_{2(g)} + 2H_{2(g)}$$

Dεερακ Ȿιηɠꜧ 4 years, 9 months ago

22g of Carbon dioxide contain ½mole of Carbon so you need ½mole carbon in methon
$$CH4 +O2 → CO2 + 2H2$$
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Dεερακ Ȿιηɠꜧ 4 years, 9 months ago

Gazab ???? 2nd book start ho gaya aapka ??
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?​?​?​?​?​?​ ?? 4 years, 9 months ago

Ha moti.. ???

Gaurav Seth 4 years, 9 months ago

1) All the alkali metals are highly reactive elements since have a strong tendency to lose the single valence s-electron to form uni positive ions having inert gas configuration.

2) This reactivity arises due to their low ionisation enthalpies and high negative values of their standard electrode potential.

3) Due to their strong tendency to lose the single valence electron ,alkali metals also act as a strong reducing agents. Reactivity of an element is measured in terms of its reducing character.

4) Ionization enthalpy is a measure of the tendency of an atom to lose electrons in the gaseous state.Thus, lower the ionization enthalpy, greater is the tendency of an element to lose electron and hence stronger is the reducing character or higher is the reactivity of the element.

5)The ionization enthalpies of alkali metal decreases down the group, therefore, their reducing character or reactivity in the gaseous state increases from Li to Cs , i.e. Li< Na< K< Rb<Cs.

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Dεερακ Ȿιηɠꜧ 4 years, 9 months ago

‽¿?¿?‽
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?​?​?​?​?​?​ ?? 4 years, 9 months ago

Aliphatic compound, any chemical compound belonging to the organic class in which the atoms are connected by single, double, or triple bonds to form nonaromatic structures.

Yogita Ingle 4 years, 9 months ago

An aliphatic compound or aliphatic hydrocarbon is an organic compound containing hydrogen and carbon atoms that are usually linked together in chains that are straight.

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Gaurav Seth 4 years, 9 months ago

The important characteristics of transition metals are:
(i)    All transition elements are metallic in nature, e.g., all are metals.
(ii)   These metals exhibit variable oxidation states.
(iii)    Transition metal atoms or ions generally form the complexes with neutral, negative and positive ligands.
(iv)    Compounds of transition metals are usually coloured.
(v)    The compounds of these metals are usually paramagnetic in nature.
(vi)    Transition metals and their compounds act as good catalysts, i.e., they show catalytic activities.
(vii)    These metals form various alloys with other metals of the series.
(viii)    These metals form interstitial compounds with C, N, B and H.

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Yogita Ingle 4 years, 9 months ago

Electron gain enthalpy generally becomes more negative across a period as we move from the left to the right. Within a group,m electron gain entahlpy becomes less negative down a group. However, adding an electron to the 2p2p-orbital leads to the greater repulsion than adding an electron to the larger 3p3p-orbital. Hence, the element with the most negative electron gain enthalpy is chlorine, and the one with the least negative electron gain enthalpy is phosphorus.

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Dεερακ Ȿιηɠꜧ 4 years, 9 months ago

The iron oxide has $$69.9%$$ iron and $$30.1%$$ dioxygen by mass.
Thus, $$100 g$$ of iron oxide contains $$69.9 g$$ iron and $$30.1 g$$ dioxygen.
The number of moles of iron present in $$100 g$$ of iron oxide are $$\frac{69.9}{55.8}=1.25$$.
The number of moles of dioxygen present in 100 g of iron oxide are $$\frac{30.1}{32}=0.94$$.
The ratio of the number of oxygen atoms to the number of carbon atoms present in one formula unit of iron oxide is $$\frac{2×0.94}{1.25}=1.5:1=3:2$$.
Hence, the formula of the iron oxide is $$Fe2O3$$<hr> $$\mathbb{YOUR\ ANSWER \ IS \ COMPLETED} $$

Kajal Verma 4 years, 9 months ago

There is O2 is mass

Kajal Verma 4 years, 9 months ago

Sry for that

Kajal Verma 4 years, 9 months ago

Don't know about mass of compound

Dεερακ Ȿιηɠꜧ 4 years, 9 months ago

What is mass of compaund ?? Without mass of compaund it's impossible to determine any formula . . ..
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?​?​?​?​?​?​ ?? 4 years, 9 months ago

Aaj kl maherbaan h pta n kyu.. ??

Royal Thakur ? 4 years, 9 months ago

Match dekh rhe Ho. ..?

Royal Thakur ? 4 years, 9 months ago

Aaj bhi aapka network Accha h.. Sirf mera he Kharab chlta h ?

?​?​?​?​?​?​ ?? 4 years, 9 months ago

Ha.. Dhakka... ???

Royal Thakur ? 4 years, 9 months ago

Dhakaa de k.. ?
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Dεερακ Ȿιηɠꜧ 4 years, 9 months ago

25

Gaurav Seth 4 years, 9 months ago

The number of atoms present in 100 amu of helium is 25 atoms.

 

To find:

Number of atoms = ?

Solution:

The number of atoms present in 100 amu of helium is to be calculated by using simple unitary method knowing that the a.m.u. is the atomic mass unit which itself represent the mass.

So thereby, we need to know the "mass of one atom" and that can be divided to know the "number of atoms".

Therefore,

The "mass of one atom" of helium is known to be 4 a.m.u.

Thereby,

  • 2 answers

Dεερακ Ȿιηɠꜧ 4 years, 9 months ago

Option 2,, H2 ,, 4 molecules

Jagdish 4 years, 9 months ago

Answer is 2 - 8g of H2 Calculating number of moles in each case we get, 44 g of CO2 has 1 mole, 8g of H2 has 4 moles and 64g of SO2 has 1 mole so the correct answer should be 2 - 8g of H2
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Meghna Thapar 4 years, 9 months ago

Viscosity is a measure of a fluid's resistance to flow.

It describes the internal friction of a moving fluid. A fluid with large viscosity resists motion because its molecular makeup gives it a lot of internal friction. The SI unit for dynamic viscosity η is the Pascal-second (Pa-s), which corresponds to the force (N) per unit area (m2) divided by the rate of shear (s-1).

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