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  • 2 answers

Ranger King 3 years, 7 months ago

He does not form molecule because of it's highly stability and also h2 and 0 bond order.

Chirag Chauhan 3 years, 7 months ago

He does not form molecule because of it's highly stability and also h2 and 0 bond order.
  • 2 answers

Sia ? 3 years, 7 months ago

Quantum mechanical model:

  1. The energy of an electron is quantized i.e. an electron can only have certain specific values of energy.
  2. The quantized energy of an electron is the allowed solution of the Schrödinger wave equation and it is the result of wave like properties of electron.
  3. As per Heisenberg’s Uncertainty principle, the exact position and momentum of an electron cannot be determined. So the only probability of finding an electron at a position can be determined and it is |ψ|2 at that point where ψ represents the wave-function of that electron.
  4. An atomic orbital is the wave-function (ψ) of an electron in an atom. Whenever an electron is described by a wave-function, it occupies atomic orbital. As an electron can have many wave-functions, there are many atomic orbitals for the electron. Every wave-function or atomic orbital have some shape and energy associated with it. All the information about the electron in an atom is stored in its orbital wave function ψ and quantum mechanics makes it possible to extract this information out of ψ.
  5. The probability of finding an electron at a point within an atom is proportional to the square of the orbital wave function i.e., | ψ | 2 at that point. | ψ |2 is known as probability density and is always positive.

Ankit Meena 3 years, 6 months ago

Yes
  • 1 answers

Balwant Kumar 3 years, 7 months ago

The general electronic configuration of halogens is np5, where n = 2-6. Thus, halogens need only one more electron to complete their octet and to attain the stable noble gas configuration. Also, halogens are highly electronegative with low dissociation energies and high negative electron gain enthalpies. Therefore, they have a high tendency to gain an electron. Hence, they act as good oxidizing agents.

  • 1 answers

Pushpender Gill 3 years, 7 months ago

S-block (Na, Mg, Ca,etc.)
  • 1 answers

Balwant Kumar 3 years, 7 months ago

In dz2 orbital, there are 2 lobes which lie on the z-axis i.e. one lobe on the +ve z-axis and other on the -ve z-axis. Other than these 2 lobes, there is also a ring shaped region around the lobe.

  • 1 answers

Chirag Chauhan 3 years, 7 months ago

Yes, because of diagonal relationship.
  • 5 answers

Anuj Kumar 3 years, 7 months ago

No I dont even need to I only asked if you were them because some old "hisab" is left with me from them

Shreya S❤ 3 years, 7 months ago

i m neither of them & i can see ,, you r not dhruv ,, and u need not to know me ,,

Anuj Kumar 3 years, 7 months ago

You are shreya sharma aur shreyas - s ! ?

Anuj Kumar 3 years, 7 months ago

And how is it prepared

Shreya S❤ 3 years, 7 months ago

R-Mg-X is gregnard's reagent ... check your book u can find rxn
  • 1 answers

Sia ? 3 years, 7 months ago

The crystals of pure blue color copper sulfate ( )

Explanation:
Experiment to prepare crystals of pure Copper Sulfate ( ) from a given  impure sample of the blue vitriol  is as follows -

Theory  -

  1. Sample + water + few drops of dilute sulfuric acid ( to prevent  hydrolysis of copper sulfate).
  2. Copper sulfate is dissolved and the insoluble  impurities are left over.
  3. The solution is filtered out. The filtrate is concentrated up to the crystallization point and then  cooled.
  4. After cooling, crystals of copper sulfate ( ) is filtered out.

Requirements - Copper sulfate sample, a beaker, a china dish, a funnel, test tube, a glass rod, an evaporating dish and a policeman

Procedure - Preparation of Solution

  • Take about 25-30 ml of water + pinch of the  powdered crude copper sulfate. Stirring the solution and repeating the same additions and stirring until some of it remains undissolved + 2-3 ml of dilute sulfuric acid (making the solution clear that prevents hydrolysis of the copper sulfate)

Formation of crystals

  • The solution is filtered out. The filtrate (left in a china dish) is concentrated up to the crystallization point and then  cooled. Heating the solution till it is reduced to about one-third of its original volume. Stir it to avoid the crust formation
  • The formation of a crust or tiny  crystals on the glass rod indicates the crystallization point. Now stop  heating.Transferring and cooling the hot saturated solution in the crystallizing dish. On cooling it we will get deep blue crystals of copper sulfate

Separation of Crystals and Drying

  • Decant + Wash the crystals with a little ethyl alcohol + water
  • Filtered on filter paper

Conclusion - The crystals of pure blue color copper sulfate ( ) are obtained that are transparent.

  • 1 answers

Sia ? 3 years, 7 months ago

A benzylic carbocation is a resonance-stabilized carbocation in each of the two equally stable major resonance forms of which the formal charge of +1 is on a benzylic carbon. eg: The lightest benzylic carbocation 1 is called the benzyl carbocation.

  • 1 answers

Pushpender Gill 3 years, 7 months ago

By polymerisation of ethyne.
  • 0 answers
  • 1 answers

Sia ? 3 years, 7 months ago

The mass of 1 proton is same as the mass of 1 Hydrogen atom. One mole of hydrogen atom weighs 1 gm. Or, 1 mole of proton will weigh 1 gm. Therefore, 200 moles of proton will weigh 200gm.

  • 1 answers

Pushpender Gill 3 years, 7 months ago

1) first calculate the no. of electrons in 1g. 2) then, multiply the value with 100, u will get the answer!!
  • 0 answers
  • 1 answers

Sia ? 3 years, 7 months ago

Heat of hydrogenation (symbol: ΔHhydro, ΔHº) of an alkene is the standard enthalpy of catalytic hydrogenation of an alkene. Catalytic hydrogenation of an alkene is always exothermic. Heat of hydrogenation of alkenes is a measure of the stability of carbon-carbon double bonds.

  • 2 answers

Aufditif Vh Fiotz8Yf 3 years, 7 months ago

Apna kam kar lode

Aryan Singh 3 years, 8 months ago

Because O has 2 lone pairs which do Repulsion among them Which cause the H²O to have a bent shape
  • 1 answers

Anay Studies 3 years, 8 months ago

The geometry of BrF5 is octa hedral
  • 1 answers

Anay Studies 3 years, 8 months ago

Sigma bond is formed from head to head overlapping of sp3 hybridised orbitals, whereas pi bond is formed by side to side overlapping
  • 1 answers

Pushpender Gill 3 years, 7 months ago

1
  • 1 answers

Anay Studies 3 years, 8 months ago

Hard water D2O Hydrogen per oxide H2O2
  • 1 answers

Yatin Mehta 3 years, 8 months ago

This reaction involves two steps : Step 1 : When the terminal ethyne react with the sodamide to give acetylides. Step 2 : When acetylides react with haloalkane (ethylchloride) to give but-1-yne as higher alkynes.
  • 0 answers

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