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Ask QuestionPosted by Vishwaraj Sindha 6 years, 10 months ago
- 3 answers
Yogita Ingle 6 years, 10 months ago
Addition of heat to a system increases the randomness in the system due to increase in molecular motions. Generally, a system at a higher temperature has greater randomness than at lower temperature. Thus, temperature too helps in the measurement of randomness of particles in a system. Heat added to a system at lower temperature causes greater randomness than in comparison to when heat is added to it at a higher temperature. Thus, entropy change is inversely proportional to the temperature of the system.
Posted by Hrithik Jadhav 6 years, 10 months ago
- 1 answers
Yogita Ingle 6 years, 10 months ago
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Sigma Bond |
Pi Bond |
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During sigma bond formation overlapping orbitals can be either one hybrid and one pure orbital or two pure orbitals and two hybrid orbitals. |
During pi bond formation overlapping orbitals are always two unhybridized orbitals. |
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Sigma bond exists independently and allows free rotation. |
Pi-bond always exists along with sigma bond and the rotation is restricted. |
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Sigma bonds are stronger bonds. |
Pi bonds are usually less powerful compared to sigma bonds. |
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Sigma bonds are formed first when atoms interact. |
Pi bonds are formed after the formation of sigma bonds. |
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During the bonding between two atoms, Only one sigma bond is formed. |
Here two pi bonds can exist between two atoms. |
Posted by Saurabh Kumar 6 years, 10 months ago
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Posted by Aastha Mittal 6 years, 10 months ago
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Sanidhya Jadaun? 6 years, 10 months ago
Gaurav Seth 6 years, 10 months ago
Tetra-tert-butylmethane is a hypothetical organic compound with formula C17H36, or ((H3C)3C)4C. It would be an alkane, specifically the most compact branched isomer of heptadecane. The systematic name is 3,3-di-tert-butyl-2,2,4,4-tetramethylpentane.

Posted by Aastha Mittal 6 years, 10 months ago
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Fatima Hussain 6 years, 10 months ago
Posted by Inthresh Selvaraj 6 years, 10 months ago
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Gaurav Seth 6 years, 10 months ago
Molar mass of Na2CO3 = (2×23)+12.00+(3×16) = 106 g mol-1
∴0.50 mol Na2CO3 means 0.50×106g = 53g
0.50 M Na2CO3 means 0.50 mol of Na2CO3 i.e. 53g of Na2CO3 are present in 1litre of the solution.
Posted by Dhruv Kumar Kalra 6 years, 10 months ago
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Neha Guupta 4 years, 9 months ago
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