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Posted by Mansi Sharma 6 years, 7 months ago
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Sia ? 6 years, 7 months ago
Atoms and molecules are too small to count. To solve this problem their numbers are expressed in terms of Avogadro’s number (NA = 6.023 1023). Mole is the number equal to Avogadro’s number just like a dozen is equal to 12, a century means 100, a score means = 20.
Mole can be defined as a unit which represents 6.023 x1023 particles of same matter.
A mole (symbol mol) is defined as the amount of substance that contains as many atoms, molecules, ions, electrons or any other elementary entities as there are carbon atoms in exactly 12 gm of
. The number of atoms in 12 gm of
is called Avogadro’s number
Posted by Riya Mahapatra 6 years, 7 months ago
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Aarzoo Sharma 6 years, 7 months ago
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Yogita Ingle 6 years, 7 months ago
The exactly half-filled and fully filled orbitals have greater stability than other configurations. The reason for their stability are symmetry and exchange energy.
(a) Symmetry: The half-filled and fully-filled orbitals are more symmetrical than any other configuration and symmetry leads to greater stability.
(b) Exchange Energy: The electrons present in the different orbitals of the same sub-shell can exchange their positions. Each such exchange leads to the decrease in energy known asExchange Energy. Greater the number of exchanges, greater the exchange energy and hence greater the stability. As the number of exchanges that take place in the half-filled and fully-filled orbitals is maximum, thus exchange energy is maximum and hence maximum stability.
Posted by Lokesh Yadav 6 years, 7 months ago
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Sia ? 6 years, 7 months ago
Energy (E) of one photon = E = hv
where h = 6.626 {tex}\times{/tex} 10-34 Js.
{tex}\nu{/tex} = 5 {tex}\times{/tex} 1014 s-1
{tex}\therefore E = \left( 6.626 \times 10 ^ { - 34 } \times 5 \times 10 ^ { 14 } \right){/tex}
{tex}= 3.313 \times 10 ^ { - 19 } J{/tex}
Energy of 1 mole of photon{tex}= \left( 3.313 \times 10 ^ { - 19 } J \right) \times \left( 6.022 \times 10 ^ { 23 } \mathrm { mol } ^ { - 1 } \right){/tex}= 1995.1 kJmol-1
Posted by Anjali Maurya 6 years, 7 months ago
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Sia ? 6 years, 7 months ago
We know, Atomic mass of H = 1.001 u
Atomic mass of N = 14.01 u
Atomic mass of O = 16.0 u
Hence, molar mass of HNO3 will be:
{tex}( 1 \times 1.001 ) + ( 1 \times 14.01 ) + ( 3 \times 16.0 ){/tex}= 63.01 u
Posted by Riya Kumari 6 years, 7 months ago
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Sia ? 6 years, 7 months ago
Hydrocarbon undergoes combustion to form carbon dioxide and water.
Molecular mass of carbon dioxide = 44 g
Mass of Carbon in 4.4 gm of carbon dioxide = {tex}\frac{12}{44} \times 4.4{/tex} = 1.2 g
Mass of Hydrogen in 2.7 gm of water = {tex}\frac{2}{18} \times 2.7{/tex} = 0.3 g
Therefore,
Total mass of Hydrogen and Carbon = (1.2 +.3)g = 1.5 g
This is the same mass before combustion.
Posted by Gaurav Gupta 6 years, 7 months ago
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Yogita Ingle 6 years, 7 months ago
1 mole of ammonia weighs 17 g.
1 molecule of ammonia = (17 / 6.023 x 1023) = 2.82 x 10-23 g = 2.82 x 10-20 kg.
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Sandeep Chaudhary 6 years, 7 months ago
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