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  • 1 answers

Sia ? 6 years, 5 months ago

1000 cm3 of 0.15 M Na2CO3 contains Na2CO3 = 0.15 mol
100 cm3 of 0.15 M Na2CO3 Will contain Na2CO3{tex}\frac { 0.15 } { 1000 } \times 100 = 0.015 \mathrm { mol }{/tex}
Molar mass of Na2CO3 = 2 {tex}\times{/tex} Na +1 {tex}\times{/tex} C +3 {tex}\times{/tex}O =2 {tex}\times{/tex}23 +1 {tex}\times{/tex} 12 + 3 {tex}\times{/tex} 16= 46 + 12 + 48 =106 g mol-1 
Therefore, Mass of Na2CO3 =Number of mole of Na2CO3 {tex}\times{/tex} Molar mass of Na2CO3 = 0.015 mole {tex}\times{/tex}106 g/mol = 1.59 g.

  • 2 answers

Aditya Maurya 6 years, 5 months ago

What you want???

Tanya Zanzad 6 years, 5 months ago

But-1-yne
  • 0 answers
  • 5 answers

Aditya Maurya 6 years, 5 months ago

There is one short trick to learn how fill all 4 orbital SSSP SPS (DPS)^2. infinte times(FPDS) Thats sit Now how to learn-SSP ne SPSe kha 2 times DPS ke bachhe infinite time FPDS(fail ho gaa)

Saniya Dutta 6 years, 5 months ago

Orbits are filled by using formula 2n^2 where n is 1, 2 ,3, 4

Tanya Zanzad 6 years, 5 months ago

Affbaus principal : also called as chemistry Ki jalebi in my language

Prashant Kumar 6 years, 5 months ago

Hunds rule,pauli's exclusion,aufbau's principal

Rekha Devi 6 years, 5 months ago

Fill the first shell with two electrons Then the 2nd shell with 8 electrons 3rd shell with 8 electrons 4th shell with 18 electrons 5th shell with 18 electrons And like that fill all
  • 1 answers

Rekha Devi 6 years, 5 months ago

By equalising the no. of atoms on both sides of the reactants and product Also satisfying the law of conversation of mass
  • 1 answers

Sia ? 6 years, 5 months ago

An atom has a nucleus surrounded by electrons. But when three oxygen atoms combine to form an O3 molecule, it becomes Ozone. So another difference between atoms and molecules is that when similar atoms combine together in varying numbers, molecules of different properties can be formed.

  • 1 answers

Sia ? 6 years, 5 months ago

Here, Z = 35, A=80
{tex}\therefore{/tex} No. of protons = Atomic no. = 35
No. of electrons = No. of protons = 35
No. of neutrons = A-Z
= 80 - 35 = 45

  • 5 answers

Yashvi Saxena 6 years, 5 months ago

Rutherford discovered protons

Suresh Kumar 6 years, 5 months ago

Rutherford

Prashant Kumar 6 years, 5 months ago

E.goldstein

Vaibhav Saini 6 years, 5 months ago

Goldstein

Ayush Vishwakarma?? 6 years, 5 months ago

Goldstein was discovered prorons by the experiment of anode rays.
  • 1 answers

Prashant Kumar 6 years, 5 months ago

32.65℅by mass
  • 1 answers

Aditya Maurya 6 years, 5 months ago

M=+1,+2,+3,+4,-1,-2-,3,-4 or reverse it
  • 1 answers

Sia ? 6 years, 5 months ago

Rydberg formula calculates the wavelengths of a spectral line in many chemical elements. The formula was primarily presented as a generalization of the Balmer series for all atomic electron transitions of hydrogen.
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  • 2 answers

Thakkar Dhruv 6 years, 5 months ago

And s=+-1/2

Thakkar Dhruv 6 years, 5 months ago

N=4,l=0,1,2,3m=-3,-2,-1,0,1,2,3
  • 1 answers

Gaurav Seth 6 years, 5 months ago

Law of multiple proportions (John Dalton 1804) states that when two elements combine to form two or more compounds, the weight of one of the elements which combines with a fixed weight of the other, bears a simple whole number ratio. For example, hydrogen and oxygen combine to form two compounds H2O (water) and H2O2(hydrogen peroxide). In water, Hydrogen 2 parts and oxygen 16 parts In hydrogen peroxide hydrogen 2 parts and oxygen 32 parts.

The weights of oxygen which combine with same weight of hydrogen in these two compounds bear a simple ratio 1 : 2. Nitrogen forms five stable oxides:

N2O Nitrogen 28 parts Oxygen 16 parts
N2O2 Nitrogen 28 parts Oxygen 32 parts
N2O3 Nitrogen 28 parts Oxygen 48 parts
N2O4 Nitrogen 28 parts Oxygen 64 parts
N2O5 Nitrogen 28 parts Oxygen 80 parts

The weight of oxygen which combines with same weight of nitrogen in the five compounds bear a ratio 16 : 32 : 48 : 64 : 80 : or 1 : 2 : 3 : 4 : 5.

  • 2 answers

Reet ... 6 years, 5 months ago

Modern abc

Adiraju Vasudev 6 years, 5 months ago

Arihant all in one
  • 2 answers

Parul Singh 6 years, 5 months ago

10^10

Gaurav Seth 6 years, 5 months ago

(i) Gram atomic mass of Au= 197 g 

Or

197g of Au contains = 6.022 x 1023

 

Therefore 1gm of Au contains = 6.022 x 1023/197*1 = 3.06 x 1021 atoms

 

(ii) Gram atomic mass of Na = 23 g

Or

23 g of Na contains atoms = 6.022x 1023

Or

1gm of Na contains atoms = 6.022x1023 /23 *1 = 26.2 x1021atoms

 

(iii) Gram atomic mass of Li = 7

Or

7g of Li contains atoms = 6.022 x 1023

Or

1g of Li contains atoms = 6.022 x 1023/7 *1= 86.0 x 1021 atoms

 

(iv) Gram atomic mass of Cl = 71 Or 71g of Cl contains atoms = 6.022x1023

Or

1 g of Cl contains atoms = 6.022x1023 /71 * 1= 8.48 x 1021atoms

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  • 1 answers

Yogita Ingle 6 years, 5 months ago

Dipole-Dipole interactions result when two dipolar molecules interact with each other through space. When this occurs, the partially negative portion of one of the polar molecules is attracted to the partially positive portion of the second polar molecule. This type of interaction between molecules accounts for many physically and biologically significant phenomena such as the elevated boiling point of water.

  • 0 answers
  • 5 answers

Ayush Vishwakarma?? 6 years, 5 months ago

Question upload karo

Urvi Sharma 6 years, 5 months ago

But I found difficulty in numerical of morality and molality

Ayush Vishwakarma?? 6 years, 5 months ago

It's ok no problem you are like my sister

Urvi Sharma 6 years, 5 months ago

Thank you so much

Ayush Vishwakarma?? 6 years, 5 months ago

Number of moles of solute which is dissolved in 1kg or 1000g of solution is called molality. Its formula is , no. Of moles of solute/mass of solute in 1kg.
  • 1 answers

Yash Goswami????? 6 years, 5 months ago

There is the whole numericals based on unit changing in chemistry so plz learn the unit values like pico,micro,mega etc.... then u will easily started solveing numericals fo ch1
  • 1 answers

Sayyada Fatima 6 years, 5 months ago

Language of Chemistry and also ARIHANT

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