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Ask QuestionPosted by Talk To Knowledege 6 years, 5 months ago
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Sia ? 6 years, 5 months ago
The following table illustrates different steps followed in determination of empirical formula of an oxide of iron using the given data -
<th scope="row">Element</th> <th scope="col">Symbol</th> <th scope="col">% by mass</th> <th scope="col">Atomic mass</th> <th scope="col">Mols of the element| Fe | 69.9 | 55.85 | {tex} \frac{69.9}{55.85}{/tex}= 1.25 | {tex}\frac{1.25}{1.25}{/tex}= 1 | 2 |
| O | 30.1 | 16.00 | {tex}\frac{30.1}{16.00}{/tex}= 1.88 | {tex}\frac{1.88}{1.25}{/tex}= 1.5 | 3 |
Thus it is concluded that the oxide contains -
2 atoms of Fe
&, 3 atoms of O
hence, the ratio of atoms in the oxide of iron
= 2 : 3
{tex}\therefore{/tex} Empirical formula - Fe2O3
Posted by Gourav Singh 6 years, 5 months ago
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Sia ? 6 years, 5 months ago
An electron shell, or a principal energy level, may be thought of as an orbit followed by electrons around an atom's nucleus.
Posted by Gourav Singh 6 years, 5 months ago
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Sia ? 6 years, 5 months ago
An electron shell, or a principal energy level, may be thought of as an orbit followed by electrons around an atom's nucleus.
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Check revision notes here : https://mycbseguide.com/cbse-revision-notes.html
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There is one point on the Fahrenheit and Celsius scales where the temperatures in degrees are equal. This is -40 °C and -40 °F.
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The empirical formula of a compound is related with its molecular formula as ,
Molecular formula = (Empirical formula)n ,
where, n is positive integer.
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