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First step:- The skeletal equation is to be written:- (MnO4)3- + (C2O4)2- ------> (Mn)+2 + CO2 Second step:- We've to seperately the balanced oxidation half and reduction half The oxidation half:- (C2O4)2- ---> 2CO2 The reduction half:- (MnO4)3- ---> (Mn)2+ Step three:- To balance oxygen, add required no. of water molecules in both halves Reduction half:- (MnO4)3- + (4H)+ ---> (Mn)2+ + 4H2O (Add H+ because it is in Acidic medium) Step four:- To balance the charge, add required no. of electrons Reduction half:- (MnO4)3- + 4H+ ---> Mn2+ + 4H2O + e- Oxidation Half:- (C2O4)2- ---> 2CO2 + 2e- Step five:- To equal the no. of electrons on both sides , multiply suitable constant Here, -2 is to be multiplied to Reduction Half, -2(MnO4)3- -8H+ ---> -2Mn2+ -8H2O - 2e- Now adding both final equations of Reduction and Oxidation We get, (C2O4) 2- - (MnO4)3- -8H+ ---> 2CO2 - 2Mn2+ -8H2O Done !!!

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Puja Sahoo? 6 years, 1 month ago

Sry bt can't understand yur question.....?

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the heat of combustion of carbon to co2 is -393.5 kJ/mol . The heat released upon formation of 35.2g of co2 from carbon and oxygen gas is

Posted by Anjali Kachhi 6 years, 1 month ago

CBSE > Class 11 > Chemistry

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What are the trends in period of ionization enthalpy

Posted by Nisha Chaurasia 6 years, 1 month ago

CBSE > Class 11 > Chemistry

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Apurv Gautam 6 years, 1 month ago

In a period it decreases as we move left to right.......

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What is hybridisation ?

Posted by Robinpreet Kaur 6 years, 1 month ago

CBSE > Class 11 > Chemistry

2 answers

Divya Thampi 6 years, 1 month ago

Intermixing of atomic orbitals having slightly energy to diff to form new orbital

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Kung Fu ?? 6 years, 1 month ago

Intermixing of atomic orbitals having slight energy diff to form new orbital is called ,,,,...

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What is solution ???

Posted by Robinpreet Kaur 6 years, 1 month ago

CBSE > Class 11 > Chemistry

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Kung Fu ?? 6 years, 1 month ago

Solution is a mixture of solute and solvent

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calculate the H+ ion concentration 1. Human blood fluid = 6.83 2. Human blood PH = 7.38

Posted by Shivam Dabas 6 years, 1 month ago

CBSE > Class 11 > Chemistry

1 answers

Shivam Dabas 6 years, 1 month ago

I don't know the answer please tell me

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Who discovered electrons

Posted by Anjali Gupta 6 years, 1 month ago

CBSE > Class 11 > Chemistry

4 answers

Piyush Gupta 6 years, 1 month ago

J.J.Thomson..

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Robinpreet Kaur 6 years, 1 month ago

Ashish oh reallyyyy ??????

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Robinpreet Kaur 6 years, 1 month ago

J.J Thomson

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@Ashish×_× Sahu 6 years, 1 month ago

I am

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A and B are van der waals constants for gases.Chlorine is more easily liquified than ethane because........ .

Posted by Chandan Subudhi 6 years, 1 month ago

CBSE > Class 11 > Chemistry

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Palak Chaudhary 6 years, 1 month ago

Because attraction is more between the particles of chlorine

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Deepjyoti Deka 6 years, 1 month ago

Because it is more electronegative than ethane

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what is jmd

Posted by Ramesh Chand 6 years, 1 month ago

CBSE > Class 11 > Chemistry

3 answers

Robinpreet Kaur 6 years, 1 month ago

Wow

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Priya Parjapati 6 years, 1 month ago

Jmd jai mata di?

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Richa Sharma 6 years, 1 month ago

Go to book shop and ask there for JMD

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Define reaction quotient Qc if Qc is less than Kc . What is the type of reaction

Posted by Sudha Sharma 6 years, 1 month ago

CBSE > Class 11 > Chemistry

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foreign reaction to a SO2 + auto reversible reaction to ISO 32 into 10 raise to power minus 3 calculate KC for the reaction at 27 degree Celsius

Posted by Kalyani Jha 6 years, 1 month ago

CBSE > Class 11 > Chemistry

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Example for heterocyclic

Posted by Channappa Bannihatti 6 years, 1 month ago

CBSE > Class 11 > Chemistry

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Because I want a easy way, chemistry is tough for me when I tried to understand it i feel bored.

Posted by Ramesh Chand 6 years, 1 month ago

CBSE > Class 11 > Chemistry

2 answers

Ramesh Chand 6 years, 1 month ago

What is JMD?

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Richa Sharma 6 years, 1 month ago

Easy way is that you learn from JMD or 333 Learn only important questions

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Exmples on oxidation number

Posted by Rahul Anuragi 6 years, 1 month ago

CBSE > Class 11 > Chemistry

3 answers

Rahul Anuragi 6 years, 1 month ago

Thanks for it

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Rahul Anuragi 6 years, 1 month ago

Send me more and more ok

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Gaurav Kumar 6 years, 1 month ago

Mno4 o is in oxide form so it will have (-2) valency . The whole charge of the compound is 0 Now Let oxidation no. Of mn be x then x+(4×(-2))=0 x-8= 0 x= +8 Hence the oxidation no. Of mn is +8

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Electron withdraw group atom in increasing

Posted by Kamala Tewari 6 years, 1 month ago

CBSE > Class 11 > Chemistry