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  • 1 answers

Abhinandan Verma 4 years, 1 month ago

Set of all digits in our number system is called integers
  • 1 answers

Gaurav Seth 4 years, 1 month ago

n(A × B) = 5(4) = 20

n[(A × B) ∩ (B × A)] = 9

 

Step by step explanation:

 

Solution :

Given:

n(A) = 5 and n(B) = 4

Thus, we have:

n(A × B) = 5(4) = 20

A and B are two sets having 3 elements in common.

Now,

Let:

A = (a, a, a, b, c) and B = (a, a, a, d)

 

Thus, we have:

(A × B) = {(a, a), (a, a), (a, a), (a, d), (a, a), (a, a), (a, a), (a, d), (a, a), (a, a), (a, a), (a, d), (b, a),

(b, a), (b, a), (b, d), (c, a), (c, a), (c, a), (c, d)}

 

(B × A) = {(a, a), (a, a), (a, a), (a, b), (a, c), (a, a), (a, a), (a, a), (a, b), (a, c), (a, a), (a, a), (a, a),

(a, b), (a, c), (d, a), (d, a), (d, a), (d, b), (d, c)}

 

[(A × B) ∩ (B × A)] = {(a, a), (a, a), (a, a), (a, a), (a, a), (a, a), (a, a), (a, a), (a, a)}

 

∴ n[(A × B) ∩ (B × A)] = 9

  • 2 answers

Nitin Jindal 4 years, 1 month ago

2x=5+3 2X=8 X=8/2 X=4 Ans.

Yogita Ingle 4 years, 1 month ago

(2x-3)=5

2x - 3 = 5

2x = 5 + 3

2x = 8

x = 8/2

x = 4

  • 0 answers
  • 1 answers

Sachi Jain 4 years, 1 month ago

Rs 164 Rs 1764
  • 2 answers

Aseem Mahajan 4 years, 1 month ago

Hope it helps?

Aseem Mahajan 4 years, 1 month ago

a,b,c,d are in GP ,means :
b² = ac
c² = bd
ad = bc

For a²+b² , b²+c² , c²+d² in GP , we need to prove :
(b²+c²)² = (a²+b²)(c²+d²)

Solving LHS:
(b²+c²)²= b⁴ + c⁴ + 2b²c²

Solving RHS:
(a²+b²)(c²+d²) = a²c²+a²d²+b²c²+b²d²
= a²c² + b²d² + 2b²c² (because ad=bc)
= (ac)² + (bd)² + 2b²c²
= b⁴ + c⁴ + 2b²c² (because ac = b² , bd = c²)
Hence ,
a²+b² , b²+c² , c²+d² are in GP
  • 1 answers

K R $ Malun Hai Na 4 years, 1 month ago

Find the value of log 8root788.5
  • 1 answers

Aseem Mahajan 4 years, 2 months ago

Give the questions
  • 1 answers

Arpit Gupta 4 years, 1 month ago

Modiji jane ?
  • 0 answers
  • 1 answers

Annu Yadav 4 years, 2 months ago

sir send me sets solution applies math 241
  • 1 answers

Arinan Aggarwal 4 years, 1 month ago

Yes according to present syllabus relation and types of relations chapter is present in applied maths
  • 1 answers

Stuti Gupta 4 years, 2 months ago

3.4157
  • 0 answers
  • 2 answers

Gokul Joshi 4 years, 2 months ago

i) {1,2,4,6,7} , ii) {1,2,4}

Mayank 3461 4 years, 2 months ago

1- (1,2,4,6,7) 2-(1,2,4)
  • 1 answers

Yogita Ingle 4 years, 2 months ago

A set is a well-defined collection of objects.
There are two methods of representing a set

  • Roster or Tabular form In the roster form, we list all the members of the set within braces { } and separate by commas.
  • Set-builder form In the set-builder form, we list the property or properties satisfied by all the elements of the sets.
  • 1 answers

Mani Kiran Batchu 4 years, 2 months ago

(1^61/64)^-2/3 =(1/64)-2/3 =(64)^3/2 =((8)^2)^3/2 =8^3 =512

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