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Posted by Rim Jain 5 years ago
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Posted by Rim Jain 5 years ago
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Posted by Sachi Jain 5 years ago
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Aseem Mahajan 5 years ago
b² = ac
c² = bd
ad = bc
For a²+b² , b²+c² , c²+d² in GP , we need to prove :
(b²+c²)² = (a²+b²)(c²+d²)
Solving LHS:
(b²+c²)²= b⁴ + c⁴ + 2b²c²
Solving RHS:
(a²+b²)(c²+d²) = a²c²+a²d²+b²c²+b²d²
= a²c² + b²d² + 2b²c² (because ad=bc)
= (ac)² + (bd)² + 2b²c²
= b⁴ + c⁴ + 2b²c² (because ac = b² , bd = c²)
Hence ,
a²+b² , b²+c² , c²+d² are in GP
Posted by Sahil Manchanda 5 years ago
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Arinan Aggarwal 4 years, 11 months ago
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Yogita Ingle 5 years, 1 month ago
A set is a well-defined collection of objects.
There are two methods of representing a set
- Roster or Tabular form In the roster form, we list all the members of the set within braces { } and separate by commas.
- Set-builder form In the set-builder form, we list the property or properties satisfied by all the elements of the sets.
Posted by Gaurav Kumar 5 years, 1 month ago
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Mani Kiran Batchu 5 years, 1 month ago
Posted by Shyamala Murthy 5 years, 1 month ago
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Gaurav Seth 5 years ago
The year 2008 is a leap year. So, it has 2 odd days.
1st day of the year 2008 is Tuesday (Given)
So, 1st day of the year 2009 is 2 days beyond Tuesday.
Hence, it will be Thursday.
Posted by Aakhya Agarwal 5 years, 1 month ago
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