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Sia ? 4 years, 4 months ago
Initial velocity, u=20m/s
Final velocity, v=0m/s
Distance, s=50m
Using relation, v2 = u2 + 2as
02 = (20)2 + 2 × a × 50
02 = 400 + 100a
−400 = 100a
a = −400 / 100 = −4m/s2
The car's deceleration must be 4m/s2.
Posted by Tanishka Dhumal 4 years, 5 months ago
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Monica ✨☄️ 4 years, 5 months ago
Hariom Waditake 4 years, 5 months ago
Posted by Srihaan Chandra 4 years, 4 months ago
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Sia ? 4 years, 4 months ago
initial velocity, u = 6 m/s and final velocity, v= -4.4 m/s
time = 0.04s
thus acceleration = (v-u)/t
a =(- 4.4 - 6)/ 0.04 = -10.4/ 0.04 = -260 m/s2
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Kunal Behl 4 years, 5 months ago
a.m.u is atomic mass unit. amu is a mass of 1/12th of mass of carbon atom. a.m.u is used for calculation ? at atomic level.
1 amu = 1/12 mass of Carbon atom = mass of 1 hydrogen atom
1 a.m.u = 1.6605 x 10-24 gms
Note: a.m.u is just another unit to measure very small masses at atomic level or mass of atoms
Measuring mass of atoms in grams is actually tiresome & amu actually makes calculation ? simpler
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Posted by Rajat Bhatt 4 years, 5 months ago
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Kunal Behl 4 years, 5 months ago
ELECTRONS are negatively charged subatomic particles.
Relative Charge on 1 electron = -1 (1.6 x 10-19 C= absolute charge)
Mass of electron = 1/1840 a.m.u (atomic mass unit)

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Shrishti Rathore 4 years, 3 months ago
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