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Ask QuestionPosted by Jiya Pasare 4 years, 2 months ago
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Aswath Gokul 4 years, 2 months ago
Posted by Jiya Pasare 4 years, 2 months ago
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Yogita Ingle 4 years, 2 months ago
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Collenchyma |
Sclerenchyma |
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Posted by Jiya Pasare 4 years, 2 months ago
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Yogita Ingle 4 years, 2 months ago
| Parenchyma Cells | Collenchyma Cells |
| Originate from ground and protoderm meristems | Originate from pro-cambium. Epidermal layer of plants are composed of collenchyma cells |
| Found in every delicate plant part | Specifically found in leaves, stems and petioles |
| Living and unspecialized cells | Living and specialized cells |
| Isodiametric generally, may vary in shape | Elongated cells |
Posted by Mohammad Tajuddin 4 years, 2 months ago
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Yogita Ingle 4 years, 2 months ago
In vitro fertilization is the most commonly used assisted reproductive technologies (ART). In vitro fertilization, as its name-fertilization is done by fusing ova from female donor and sperm from the male donor outside the body under strict laboratory conditions. This results in a zygote or famously known as test tube baby. After the embryo culturing, an embryo is transferred to the uterus of the mother. This method is commonly done in case of women with damaged or clogged Fallopian tubes.
Gaurav Seth 4 years, 2 months ago
In healthy women fertilisation of egg by sperm take place in the oviduct or fallopian tube.The oviduct of some women are blocked due to some reason.Such women cannot produce babies in the normal way because the eggs released by their ovary cannot meet the sperm and get fertilised in the oviduct. Such women who cannot produce babies are called sterile.Even the sterile women can have women by using the in-vitro fertilisation technique. The fertilisation of an egg with sperm is carried out in a glass dish or glass tube rather than in the body of a woman.This is commonly known as test-tube baby technique or IVF.
Posted by Laiba Mahwish 4 years, 2 months ago
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Rutaja Singh 4 years, 2 months ago
Madhusmita Sahu 4 years, 2 months ago
Posted by Hanshika (Honey) 4 years, 2 months ago
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Madhusmita Sahu 4 years, 2 months ago
Posted by Hanshika (Honey) 4 years, 2 months ago
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Hanshika (Honey) 4 years, 2 months ago
Madhusmita Sahu 4 years, 2 months ago
Posted by Ishita Agrawal 4 years, 2 months ago
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Meghna Thapar 4 years, 2 months ago
The main sources of pollution are household activities, factories, agriculture and transport. Once they have been released into the environment, the concentration of some pollutants is reduced by dispersion, dilution, deposition or degradation. Pollution can take the form of chemical substances or energy, such as noise, heat or light. Pollutants, the components of pollution, can be either foreign substances/energies or naturally occurring contaminants. Pollution is often classed as point source or nonpoint source pollution.
Posted by Shruti Agrawal 4 years, 2 months ago
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Gaurav Seth 4 years, 2 months ago
Nature of liquid : There are two types of liquid according to the nature of evaporation.
1) Volatile
2) Non Volatile
Volatile liquids have much higher evaporation rate than the non volatile liquids. Volatile liquid can evaporate in very short amount of time even in the room temperature and the non volatile liquid needs external heat application for evaporation.
Yogita Ingle 4 years, 2 months ago
Nature of liquid : There are two types of liquid according to the nature of evaporation.
1) Volatile
2) Non Volatile
Volatile liquids have much higher evaporation rate than the non volatile liquids. Volatile liquid can evaporate in very short amount of time even in the room temperature and the non volatile liquid needs external heat application for evaporation.
Posted by Madhusmita Sahu 4 years, 2 months ago
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Madhusmita Sahu 4 years, 2 months ago
Devansh Tiwari 4 years, 2 months ago
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Posted by Anushka Singh 4 years, 2 months ago
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Madhusmita Sahu 4 years, 2 months ago
Yogita Ingle 4 years, 2 months ago
The invention of the electron microscope by Max Knoll and Ernst Ruska at the Berlin Technische Hochschule in 1931 finally overcame the barrier to higher resolution that had been imposed by the limitations of visible light.
Posted by Sneha Singh 4 years, 2 months ago
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Yogita Ingle 4 years, 2 months ago
15% acid = 15g/100ml
Density is 1.02g/ml, so that makes 15gm in 102gm of solution
Now subtracting the weight of acid from the total weight of the solution
= 102 g – 15 g
= 87 g of water
To find out how much acid is present in 100g of water, we do the following,
100ml x 87g /15g
= 17.24/100 g of water
The density of water is said to be 1g/ml, therefore its concentration will be 17.24/100 ml or 100g of water
Hence,
The mass by volume percentage of H2SO4 will be 17.24% w/w
Posted by Sneha Singh 4 years, 2 months ago
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Gaurav Seth 4 years, 2 months ago
Given volume of solvent = 70 mL
Given volume of solute = 5 mL
Total volume of solution = 70 + 5 = 75 mL
Volume percent = ( volume of solute ) / ( volume of solution ) * 100
= (5 / 75) * 100
= 6.67 %
Posted by Jasmine Kaur 4 years, 2 months ago
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Yogita Ingle 4 years, 2 months ago
To concert Kelvin scale into Celsius scale we have to subtract 273 so
(a) 303K = 303 - 273 = 30 ºC,
(b) 570K = 570-273 = 297 ºC
Posted by Jasmine Kaur 4 years, 2 months ago
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Madhusmita Sahu 4 years, 2 months ago
Yogita Ingle 4 years, 2 months ago
Temperatures can be converted from Celsius to Kelvin by adding 273 to the the Celsius Scale.
We have been given 3 temperatures here which are in the Celsius Scale.
25°C, 38°C and 66°C
To convert all of them to the Kelvin Scale, add 273 to all of them.
25 + 273 = 298 K
38 + 273 = 311 K
66 + 273 = 339 K
Read more on Brainly.in - https://brainly.in/question/12484519#readmore
Posted by Sneha Singh 4 years, 2 months ago
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Yogita Ingle 4 years, 2 months ago
Mass of solute (salt)=40 g
Mass of solvent (water)=320 g
We know,
Mass of solution =Mass of solute +Mass of solvent
=40g+320g
=360 g
Mass percentage of solution
=Mass of solute /Mass of solution ×100
= 40/360 × 100 =11.1%
Posted by Shweta Sharma 4 years, 2 months ago
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Madhusmita Sahu 4 years, 2 months ago
Posted by Jasmine Kaur 4 years, 2 months ago
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Suzanne Smitha 4 years, 2 months ago
Hanshika (Honey) 4 years, 2 months ago
Madhusmita Sahu 4 years, 2 months ago
Posted by Madhusmita Sahu 4 years, 2 months ago
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Hanshika (Honey) 4 years, 2 months ago
Posted by Madhusmita Sahu 4 years, 2 months ago
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Suzanne Smitha 4 years, 2 months ago
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Posted by Madhusmita Sahu 4 years, 2 months ago
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Yogita Ingle 4 years, 2 months ago
The melting point and the freezing point are usually the same temperature. The melting point is the temperature at which a solid turns into a liquid, while the freezing point is the temperature at which a liquid turns into a solid. The transition of matter is same. For water, it is 0 degrees Celsius. When a block of ice is heated above 0 degrees Celsius, it melts, while a glass of water is cooled below 0 degrees Celsius it freezes. There are a few substances that have different melting and freezing points. Example, agar melts at 85 degrees Celsius but freezes between 32 and 40 degrees Celsius. That is called “hysteresis,” and it’s not very common phenomenon.
Posted by Abhishek Anand 4 years, 2 months ago
- 1 answers
Gaurav Seth 4 years, 2 months ago
1 . Name types of simple tissues .
Ans . The types of simple tissues are parenchyma, collenchyma, sclerenchyma and aerenchyma
Parenchyma is divided into two types :
- Chlorenchyma
- Aerenchyma.
Posted by Shraddha Verma 4 years, 2 months ago
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Madhusmita Sahu 4 years, 2 months ago
Devansh Tiwari 4 years, 2 months ago
Madhusmita Sahu 4 years, 2 months ago
Posted by Dhanyatha S Maddodi 4 years, 2 months ago
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Gaurav Seth 4 years, 2 months ago
Increase in the pressure on the surface of a gas decreases the volume of the gas with increasing its density. The particles start moving in straight lines and also collide with the wall of the container and this collision enhances the inter particle forces and increases the fluidization behaviour.
We know that the particle of gas are very far apart which means there is a large gap between the particle. So, when pressure is applied, these gas particle come close to one another. When these particles come closer, the force of attraction comes into play and the gaseous state change into liquid state. When some more pressure is applied the liquid state further changes into solid state.
Posted by Mohit Gakhar 4 years, 2 months ago
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Posted by Deeya.J.S Nair 4 years, 2 months ago
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Posted by Soumya Shrivas 4 years, 2 months ago
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Anmol Dwivedi 4 years, 2 months ago
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Posted by Aishwarya Satish 4 years, 2 months ago
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Meghna Thapar 3 years, 11 months ago
- Equation For Velocity-Time Relation:
Consider the velocity-time graph of an object that moves under uniform acceleration. Initial velocity of the object is u and then it increases to v in time t. The velocity changes at a uniform rate a.
The perpendicular lines BC and BE are drawn from point B on the time and the velocity axes respectively, so that the initial velocity is represented by OA, the final velocity is represented by BC and the time interval t is represented by OC. BD = BC – CD, represents the change in velocity in time interval t.
Let us draw AD parallel to OC. From the graph, we observe that BC = BD + DC = BD + OA
Substituting BC = v and OA = u,
we get v = BD + u i.
or BD = v – u ii.
From the velocity-time graph,
The acceleration of the object is given by a = Change in velocity/time taken
= BD/AD = BD/OC
Substituting OC = t, we get
a = BD/t
BD = at iii.
Using the equations ii. & iii. We get,
v = u + at
- Equation For Position - Time Relation:
Let us consider that the object has travelled a distance s in time t under uniform acceleration a. The distance travelled by the object is obtained by the area enclosed within OABC under the velocity-time graph AB. Thus, the distance s travelled by the object is given by
s = area OABC (which is a trapezium)
= area of the rectangle OADC + area of the triangle ABDM.
= OA × OC + 1/2 (AD × BD)
Substituting OA = u, OC = AD = t and BD = at, we get
s = u × t + 1/2 (t×at)
or
s = u t + 1/2 a t2
- Equation For Position - Velocity Relation:
From the velocity-time graph, the distance s travelled by the object in time t, moving under uniform acceleration a is given by the area enclosed within the trapezium OABC under the graph. That is,
s = area of the trapezium OABC = (OA + BC) X OC/2
Substituting OA = u, BC = v and OC = t,
We get
s= (u+v) t/2
From the velocity-time relation
We get
t= v - u/a
We have
s = (v + u) x (v – u)/2a
or 2as = v2 – u2
Posted by Hakeem Urva Tul Wusqa 4 years, 2 months ago
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Posted by K Kaviya 4 years, 2 months ago
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Yogita Ingle 4 years, 2 months ago
- Let the mass of earth = M.
- Let the mass of the object = m.
- Distance between the the earth's centre and object = Radius of the earth = R.
- Therefore,
- Gravitational Force = F = GMm/ R 2
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Yogita Ingle 4 years, 2 months ago
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