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Ask QuestionPosted by G. Harini ???????? 5 years, 2 months ago
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Om Patel 5 years, 2 months ago
Neeta Madiraju 5 years, 2 months ago
Posted by Abhishek Sali 5 years, 2 months ago
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Yogita Ingle 5 years, 2 months ago
A curve is a shape or a line which is smoothly drawn in a plane having a bent or turns in it. For example, a circle is an example of curved-shape.
Posted by Subobh Sharma 5 years, 2 months ago
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Gaurav Seth 5 years, 2 months ago
Posted by Harshika Sambeta 5 years, 2 months ago
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Ayush Laxme 5 years, 2 months ago
$Hrey@Sh P@Ndey 5 years, 2 months ago
Posted by Shruti Dhamanse 5 years, 2 months ago
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Posted by Subobh Sharma 5 years, 2 months ago
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Posted by Vanshika Kumari 5 years, 2 months ago
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Gaurav Seth 5 years, 2 months ago
Solutions:
| Marks | Tally Marks | Number of Students | |
| 1 | || | 2 | |
| 2 | ||| | 3 | |
| 3 | ||| | 3 | |
| 4 | || |
7 | |
| 5 | | |
6 | |
| 6 | || |
7 | |
| 7 | ![]() |
5 | |
| 8 | |||| | 4 | |
| 9 | ||| | 3 |
(a) The students who got marks equal to or more than 7 are the students who got marks as either of 7, 8 and 9. Therefore number of these students
= 5 + 4 + 3
= 12
(b) The students who got marks below 4 are the students who got marks as either of 1, 2 and 3. Therefore number of these students are
= 2 + 3 + 3
= 8
Posted by Devanshi Brothra 5 years, 2 months ago
- 1 answers
Gaurav Seth 5 years, 2 months ago
The answer is given below :
We take the two digits 2 and 3.
Then, we make the following four digit numbers with the condition that each digit be equal in numbers, i.e., twice in times.
So, the numbers are
3322, 3232, 3223, 2233, 2323, 2332
Thus the greatest number is 3322
and the smallest number is 2233.
Hence, six different numbers can be made.
Posted by Shruti Jha 5 years, 2 months ago
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Posted by Dhyey Rupareliya 5 years, 2 months ago
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Neeta Madiraju 5 years, 2 months ago
= 1-475-475-475-475+1900
Adding all 475 gives the result 475
=1-1900+1900
=1-0
=1
Posted by Amit Bhai 5 years, 2 months ago
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Posted by Aman Kumar 5 years, 2 months ago
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Posted by Manav Gharwal 5 years, 2 months ago
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Gaurav Seth 5 years, 2 months ago
2. Solve:
(a) 1 / 18 + 1 / 18
(b) 8 / 15 + 3 / 15
(c) 7 / 7 – 5 / 7
(d) 1 / 22 + 21 / 22
(e) 12 / 15 – 7 / 15
(f) 5 / 8 + 3 / 8
(g) 1 – 2 / 3 (1 = 3 / 3)
(h) 1 / 4 + 0 / 4
(i) 3 – 12 / 5
Solutions:
(a) 1 / 18 + 1 / 18
= (1 + 1) / 18
= 2 / 18
= 1 / 9
(b) 8 / 15 + 3 / 15
= (8 + 3) / 15
= 11 / 15
(c) 7 / 7 – 5 / 7
= (7 – 5) / 7
= 2 / 7
(d) 1 / 22 + 21 / 22
= (1 + 21) / 22
= 22 / 22
= 1
(e) 12 /15 – 7 / 15
= (12 – 7) / 15
= 5 / 15
= 1 / 3
(f) 5 / 8 + 3 / 8
= (5 + 3) / 8
= 8 / 8
= 1
(g) 1 – 2 / 3
= 3 / 3 – 2 / 3
= (3 – 2) / 3
= 1 / 3
(h) 1 / 4 + 0
= 1/ 4
(i) 3 – 12 / 5
= 15 / 5 – 12/ 5
= (15 – 12) / 5
= 3 / 5
Posted by 23.Samarth Dhaiya 5 years, 2 months ago
- 3 answers
Posted by Dipesh Mishra 5 years, 2 months ago
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Posted by Sukhmanpreet Kaur 5 years, 2 months ago
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Samiksha .Sambyal 5 years, 2 months ago
1Thank You