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Sia ? 6 years, 5 months ago

The smallest 2-digit number is 10.

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Arpita Bhoi 8 years, 2 months ago

All the natural numbers including 0 is known as whole number

Saketh M 8 years, 2 months ago

Add 0 to the counting numbers,then they are whole numbers.The smallest whole number is 0 and the greatest whole number is undefined. Eg. 0,1,2,3,4,5,6,7,8,9,.............and so on

Div Sharma 8 years, 2 months ago

A counting which add all no. Is called whole no. 0,1,2,3,4,5,6,7,8,9,10..... Smallest whole no. Is
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Saketh M 8 years, 2 months ago

Answer is -4

Div Sharma 8 years, 2 months ago

-4
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Saketh M 8 years, 2 months ago

Yes,it is divisible by 9..... How means..... Divisibility rule of 9 is sum of the digits must be divisible by 9 then 429714 sum is 4+2+9+7+1+4=27 is divisible by 9 So,429714 is divisible by 9
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Sia ? 6 years, 5 months ago

295612

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Saketh M 8 years, 2 months ago

It is the easiest subject in the world

Bhashat Borthakur 8 years, 2 months ago

It is the hardest subject
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Div Sharma 8 years, 2 months ago

1 score =20 kite
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Anurag Goyal 8 years, 2 months ago

Bolan pass
A.B
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Sia ? 6 years, 5 months ago

An algebraic expression is a mathematical phrase that can contain ordinary numbers, variables (like x or y) and operators (like add,subtract,multiply, and divide). Here are some algebraic expressions: a + 1. a - b. 3x.

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Anurag Goyal 8 years, 2 months ago

It is an point. Example-: 52.1
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Anurag Goyal 8 years, 2 months ago

62.5
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Vipul Pandey 8 years, 2 months ago

A principal is who guide children and teach him Good things.
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Prapti Chaudhury 8 years, 2 months ago

2,3,5,7,11,13,17,19

Ashutoshnn Giri 8 years, 2 months ago

Numbers which have only two factors namely 1 and the numbers itself are called prime numbers : exm 2,3,5,7 11
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2+1
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Shivam Kumar 8 years, 2 months ago

3
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Sia ? 6 years, 5 months ago

According to question we have to find the least number which when divided by 20, 25, 35 and 40 leaves remainders 14, 19, 29 and 34 respectively.

Take the  LCM of 20, 25, 35 and 40 i.e., 
20 = 2 {tex}\times{/tex} 2 {tex}\times{/tex} 5
25 = 5 {tex}\times{/tex} 5
35 = 1 {tex}\times{/tex} 5 {tex}\times{/tex} 7
40 = 2 {tex}\times{/tex} 2 {tex}\times{/tex} 2 {tex}\times{/tex} 5
Now LCM of 20, 25, 35 & 40  =  2 {tex}\times{/tex} 2 {tex}\times{/tex} 5 {tex}\times{/tex} 5 {tex}\times{/tex} 7 {tex}\times{/tex} 2 = 1400
If the number 1400 is divided by 20, 25, 35, 40 it leaves a remainder 14, 19, 29, 34.
i.e. 6 less than the divisor in each case
Hence, the required number = 1400 - 6 = 1394.

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