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Ask QuestionPosted by Rishav Singh 7 years, 10 months ago
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Posted by Anju Garg 7 years, 10 months ago
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Yogita Ingle 7 years, 10 months ago
Length of the floor = 150 cm
Breadth of the floor = 180 cm
Area of the room = (length × breadth) = (150 × 180) cm2 = 27000 cm2
Length of the tile = 15 cm
Area of the tile = (side × side) = 15 × 15 = 225 cm2
Number of tiles required to cover the floor = {tex}\frac{Area\;of\;the\;floor}{Area\;of\;one\;tile}{/tex}= {tex}\frac{27000}{225}{/tex} = 120 tiles.
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Mr Gen Jelly 7 years, 10 months ago
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Sia ? 6 years, 5 months ago
{tex}Median = l_1+ \frac{(\frac {n}{2} - c.f.)}{f} \times i{/tex}
where
{tex}l_1 {/tex} = lower limit of the median class
c.f. = cumulative frequency of the class preceding the median class
f = simple frequency of the median class
i = class interval of the median group or class.
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Yogita Ingle 7 years, 10 months ago
Area of square = 49 sq. cm
Side of square = √49 = 7 cm.
Perimeter of square = 4 × side = 4 × 7 = 28 cm
Perimeter of square = perimeter of rectangle = 28 cm
Perimeter of rectangle = 2(length) + 2 (breadth)
28 = 2(9.3 ) + 2 (breadth)
28 = 18.6 + 2(breadth)
2 (breadth) = 28 – 18.6 = 9.4
breadth = 4.7 cm
Area of rectangle = length × breadth = 9.3 × 4.7 = 43.71 sq. cm
So area of rectangle is greater than area of square.
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