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Preeti Dabral 1 year, 10 months ago
As per given condition, we have
Perimeter of a rectangle = 2 (Length of the rectangle + Breadth of the rectangle)
Which means the perimeter of a rectangle is twice the sum of its length and breadth.
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Preeti Dabral 1 year, 11 months ago
Length of rectangular hall = 14 m
Breadth of rectangular hall = 12 m
Area of hall ={tex}\text { Length } \times \text { Breadth }=14 \times 12=168 \mathrm{sq} . \mathrm{m} .{/tex}
Side of square tile = 10 cm = 0.1 m
Area of square tile ={tex}0.1^2=0.01 s q . m{/tex}
No. of tiles are required = {tex}\frac{168}{0.01}=16800{/tex}
Hence 16800 tiles are required .
Posted by Rekha My Mom 1 year, 11 months ago
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Preeti Dabral 1 year, 11 months ago
Let the radius of the base of the cone be r cm.
h = 15 cm, Volume = 1570 cm3
⇒{tex}{1\over3}\pi r^2h{/tex}= 1570
⇒{tex}1\over3{/tex} × 3.14 × r2 × 15 = 1570
⇒ {tex}r^2={{1570\times3}\over3.14\times15}{/tex} ⇒ {tex}r^2=100{/tex}
⇒ {tex}r=\sqrt{100}{/tex} ⇒ r = 10 cm.
∴ the radius of the base of the cone is 10 cm.
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Rituresh Yadav 1 year, 10 months ago
0Thank You