CBSE > Class 06 > Maths (OLD) | CBSE Board | Homework Help

As per given condition, we have
Perimeter of a rectangle = 2 (Length of the rectangle + Breadth of the rectangle)
Which means the perimeter of a rectangle is twice the sum of its length and breadth.

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How to LCM and hcf

Posted by Jyotirmayee Sahu 2 years, 4 months ago

CBSE > Class 06 > Maths (OLD)

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Preeti Dabral 2 years, 4 months ago

What is your question ?

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ex 11.1

Posted by K Pandey 2 years, 4 months ago

CBSE > Class 06 > Maths (OLD)

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Viraj Sachin Kadam 2 years, 4 months ago

Chaptit padin

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K Pandey 2 years, 4 months ago

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Algebra ex 11.1

Posted by K Pandey 2 years, 4 months ago

CBSE > Class 06 > Maths (OLD)

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Find the perimeter of a regular hexagon with each side measuring 6cm

Posted by Mikel Bharnat 2 years, 4 months ago

CBSE > Class 06 > Maths (OLD)

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Hazel Kaur Bhachu 2 years, 4 months ago

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Shubham Gohel 2 years, 4 months ago

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Rohan Kumar 2 years, 4 months ago

A regular hexagon has Side =6 Formula=6×6 =36 Rohan kumar

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Mayank Singh 2 years, 4 months ago

36 cm

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The cost of fencing a square field at rupees 125 per metre is rupees 8000 find the area of the field

Posted by Shristi Gupta 2 years, 4 months ago

CBSE > Class 06 > Maths (OLD)

1 answers

Mayank Singh 2 years, 4 months ago

Vtfh

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26.225 + 41.0002 - 0.0007

Posted by Unknown ---- 2 years, 4 months ago

CBSE > Class 06 > Maths (OLD)

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Mayank Singh 2 years, 4 months ago

67.2259

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Chaitanya Chaitu 2 years, 4 months ago

67.2245

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Find the area of rectangle whose length and breadth are Length= 25cm Breadth= 9m.

Posted by Mohammad Adi 2 years, 4 months ago

CBSE > Class 06 > Maths (OLD)

3 answers

Mayank Singh 2 years, 4 months ago

Area of a rectangle=L×B =25×9 =225m MÂYÃÑK ẞÎÑGH

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Mayank Singh 2 years, 4 months ago

225m

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Khyati Gupta 2 years, 4 months ago

225m

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5-19/2

Posted by Drashti Chadar 2 years, 4 months ago

CBSE > Class 06 > Maths (OLD)

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Mayank Singh 2 years, 4 months ago

-14/2

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Drashti Chadar 2 years, 4 months ago

-14/2

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3. Out of 60 students in class, 16 like strawberry ice cream,20 like chocolate ice cream,15 like mango ice cream and remaining like vanilla ice cream Find the ratio of A. Number of students linking strawberry ice cream to number of students linking chocolate ice cream

Posted by Account Deleted 2 years, 4 months ago

CBSE > Class 06 > Maths (OLD)

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Khyati Gupta 2 years, 4 months ago

16:20 = 4:5

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Account Deleted 2 years, 4 months ago

16:29 and in lowest form =4:5

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Angel Bokan 2 years, 4 months ago

16:20(reduced) 4:5

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Arnav Yadav 2 years, 4 months ago

668

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1 to 30 Tables

Posted by Roshni Kumari 2 years, 4 months ago

CBSE > Class 06 > Maths (OLD)

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Kanika Yadav 2 years, 4 months ago

Hhiop

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A rectangular hall is of length 14 m and breadth 12m.how many square tiles of side 10cm are needed to cover the floor of the hall?

Posted by Shashank . K 2 years, 4 months ago

CBSE > Class 06 > Maths (OLD)

2 answers

Preeti Dabral 2 years, 4 months ago

Length of rectangular hall = 14 m

Breadth of rectangular hall = 12 m

Area of hall = $\text { Length } \times \text { Breadth }=14 \times 12=168 \mathrm{sq} . \mathrm{m} .$

Side of square tile = 10 cm = 0.1 m

Area of square tile = $0.1^2=0.01 s q . m$

No. of tiles are required = $\frac{168}{0.01}=16800$

Hence 16800 tiles are required .

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Shashank . K 2 years, 4 months ago

Thank you

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The height of the cone is 15 cm if it's vol is 1570 cm find the dieter of the base

Posted by Rekha My Mom 2 years, 4 months ago

CBSE > Class 06 > Maths (OLD)

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Preeti Dabral 2 years, 4 months ago

Let the radius of the base of the cone be r cm.
h = 15 cm, Volume = 1570 cm³
⇒ ${1\over3}\pi r^2h$ = 1570
⇒ $1\over3$ × 3.14 × r² × 15 = 1570
⇒ $r^2={{1570\times3}\over3.14\times15}$ ⇒ $r^2=100$
⇒ $r=\sqrt{100}$ ⇒ r = 10 cm.
∴ the radius of the base of the cone is 10 cm.