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Yogita Ingle 6 years, 2 months ago
Given:
In ∆ABC , 3∠A= 4∠B= 6∠C
Let x= 3∠A= 4∠B= 6∠C
X=3∠A
∠A= x/3
X=4∠B
∠B= x/4
X=6∠C
∠C= x/6
By angle sum property
∠A+∠B+∠C= 180°
Put the value of ∠A, ∠B, ∠C
X/3+x/4+x/6= 180°
L.c.m of 3,4,6 = 12
(4x + 3x +2x) /12 = 180°
9x = 12 × 180
X= (12× 180) /9
X= 240°
∠A= x/3
∠A= 240/3 = 80°
∠B= x/4
∠B= 240/4= 60°
∠C= x/6
∠C= 240/6 = 40°
Hence the angles be
∠A=80°
∠B=60°
∠C= 40°
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Rashi Arora 6 years, 2 months ago
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