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8000A⁰ then find E

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8000A⁰ then find E

    • Posted by Vikas Jat 1 year, 6 months ago

    Rajasthan Board > Class 12 > Physics
    • 1 answers

    Piyush Jangid 1 year, 3 months ago

    If 8000 A° is radius btw two charges Then find electric field intensity if two charges is electron and proton Ans. A°=10^-10 Then ,8000×10^-10 8×10^3×10^-10 =8×10^-7 = Electric field intensity at a point at dis. R =Vector E =kq/r^2 =E= 9×10^9×1.6×10^-19/(8×10^-7)^2 E=22×10^-4 Ans....

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