What is the numbar of photons …
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Preeti Dabral 2 years, 4 months ago
Energy of photon (E) = hcλ
h = 6.626 × 10-34 Js, c= 3×108 ms-1, λ = 4000 pm = 4000 × 10-12 = 4 ×10-9 m
∴ Energy of photon (E) = (6.626×10−34Js)×(3×108ms−1)(4×10−9m)= 4.969 × 10-17 J
Now, 4.969 × 10-17 J is the energy of photon = 1
∴1 J is the energy of photons = 14.969×10−17= 2.012 ×1016 photons.
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