Sin3x+Sin2x-Sinx =4SinxCosx/2cox3x/2

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Sin3x+Sin2x-Sinx =4SinxCosx/2cox3x/2

Posted by Rohitr Kumar 2 years, 4 months ago

Bihar Board > Class 11 > Mathematics

1 answers

Prince Sharma 10 months, 1 week ago

LHS = sin3x + sin2x - sinx = (sin3x - sinx) + sin2x =(2cos2x × sinx) + sin2x =(2cos2x sinx) + (2sinx cosx) =2sinx(cos2x + cosx) = 2sinx[2cos(3x/2) cos(x/2)] = 4 sinx cos(x/2) cos(3x/2)= RHS Hence proved.

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