X(X^2-1)dx/dy=1:y=0 x=2
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Posted by Ashish Varma 3 years, 11 months ago
- 2 answers
Account Deleted 3 years, 11 months ago
I guess you want to find the Particular Solution of the equation x(x2−1)dxdy=1 at y=0,x=2
It can be written as=>x(x2−1)dx=dy
=> (x3−x)dx=dy
On Integrating both side
x44−x22=y + c ....................1
Put x=2 & y=0 in equation 1
c = 2
Now put value of c in 1
x44−x22=y+2
This is the Particular Solution of given differential equation.
Equation 1 is the General Solution of given differential equation.
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Posted by Kanika Mishra 2 years, 11 months ago
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Shekhar Yadav 3 years, 9 months ago
0Thank You