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Factorize using identity: a) 27x³+ 125³ …

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Factorize using identity: a) 27x³+ 125³ b) 9x²+6xy+y² c) 27x³+y³+ z³-9xyz

    • Posted by Deepanshu Kumar Garg 4 years, 4 months ago

    ICSE & ISC > Class 09 > Mathematics
    • 2 answers

    Sartaj Ahmad 4 years, 3 months ago

    (a) 27x³+ 125³ =(3x)³+ 5³ =(3x+5) {(3x)²+ 5²-(3x)(5)} =(3x+5)(9x²+ 25-15x) (b) 9x²+6xy+y² =(3x)²+2(3x)(y)+y² =(3x+y)² (c) 27x³+y³+ z³-9xyz =(3x)³+(y)³+ (z)³-3(3x)(y)(z) =(3x+y+z){(3x)²+y²+y²-3xz-yz-3xz)} =(3x+y+z(9x²+y²+y²-3xz-yz-3xz)

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    Deepanshu Kumar Garg 4 years, 4 months ago

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