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If the HCF of 210 and …

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If the HCF of 210 and 55 is expressible in the form to 10 × 5 + 55 y then y is
  • 1 answers

Arati Dodamani 7 years ago

HCF of 210 and 55 is 5 10 X5 +55y = 5 50 + 55y =5 55y = 5 - 50 55y = - 45 y=-45/55 y=-9/11
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