Calculate coulombian force between a proton …
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Posted by Tanya Chauhan 5 years, 3 months ago
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Yogita Ingle 5 years, 3 months ago
Charge of electron,{tex} q_1=-1.6\times 10^{-19}\ C{/tex}
Charge of proton, {tex}q_2=+1.6\times 10^{-19}\ C{/tex}
Distance between them,{tex} r=0.8\times 10^{-15}\ m{/tex}
Coulomb's force is given by :
{tex}F=k\dfrac{q_1q_2}{r^2}{/tex}
{tex}F=9\times 10^9\times \dfrac{1.6\times 10^{-19}\ C\times 1.6\times 10^{-19}\ C}{(0.8\times 10^{-15}\ m)^2}{/tex}
{tex}F=360\ N{/tex}
Hence, the force between the proton and electron is 360 N and it is attractive in nature.
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