किसी क्षण t पर एक कण …

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किसी क्षण t पर एक कण की स्थिति x=4t^2-15t+20 मीटर से व्यक्त की गयी है इससे शून्य समय पर कण की स्थिति,वेग तथा त्वरण ज्ञात कीजिए

Posted by क्षत्रिय अँशुल सिहँ 5 years, 2 months ago

UP Board > Class 12 > गणित

1 answers

Vikash Badhautiya 5 years, 2 months ago

Sir 5.1 ke saval bataeye

1Thank You

ANSWER

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