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If Sn denotes,the sum of the first n terms of an A.P.prove that S12=3(S8_S4)

Posted by Jobanpreet Dhillon 6 years, 9 months ago

Entrance Exam > JEE main > Mathematics

1 answers

Chandrashekhar Wankhede 6 years, 8 months ago

Sn = (n/2)(2a+(n-1)d)

S12= (12/2)(2a+(12-1)d)=12a+66d

Similarly

S8= (8/2)(2a+(8-1)d)= 8a+28d

S4= (4/2)(2a+(4-1)d) = 4a+6d

RHS = 3(S8-S4)= 3(8a+28d-4a-6d)

RHS =3(4a+22d) = 12a + 66d = LHS

Hence Proved

0Thank You

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