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Why tertiary and secondary amine do not react to carbylamine test

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What is peptisation

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Peptisation is the process which is the primary cause for the formation of colloidal particles in dispersion medium. It requires an electrolyte known as peptizing agent for the completion of the process. It plays a vital role for understanding precipitation reactions that occur in aqueous solution. It has a number of uses:
 It can be used in nano particle synthesis.
 It can be used to split large grouping into smaller particles.
 It is used for synthesizing Titania.
 It helps in filtrating colloidal solution.
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Ans. Peptization is the process responsible for the formation of stable dispersion of colloidal particles in dispersion medium. In other words it may be defined as a process of converting a precipitate into colloidal sol by shaking it with dispersion medium in the presence of small amount of electrolyte.
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Effect of demonetization one economy and ppc? (6 marks)

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Ans. Demonetization as a cleaning exercise may produce several good things in the economy. At the same time, it creates unavoidable income and welfare losses to the poor sections of the society who gets income based on their daily work and those who doesn’t have the digital transaction culture.Following are the main impacts.
 Demonetization is not a big disaster like global banking sector crisis of 2007; but at the same time, it will act as a liquidity shock that disturbs economic activities
 Liquidity crunch (short term effect): liquidity shock means people are not able to get sufficient volume of popular denomination especially Rs 500. This currency unit is the favourable denomination in daily life. It constituted to nearly 49% of the previous currency supply in terms of value. Higher the time required to resupply Rs 500 notes, higher will be the duration of the liquidity crunch.
 Welfare loss for the currency using population: Most active segments of the population who constitute the ‘base of the pyramid’ uses currency to meet their transactions. The daily wage earners, other labourers, small traders etc. who reside out of the formal economy uses cash frequently. These sections will lose income in the absence of liquid cash. Cash stringency will compel firms to reduce labour cost and thus reduces income to the poor working class.
 Consumption will be hit: When liquidity shortage strikes, it is consumption that is going to be adversely affected first.
 Loss of Growth momentum India risks its position of being the fastest growing largest economy: reduced consumption, income, investment etc. may reduce India’s GDP growth as the liquidity impact itself may last three four months.
 Impact on bank deposits and interest rate: Deposit in the short term may rise, but in the long term, its effect will come down. The savings with the banks are actually liquid cash people stored. It is difficult to assume that such ready cash once stored in their hands will be put into savings for a long term. They saved this money into banks just to convert the old notes into new notes.
 Impact on black money: Only a small portion of black money is actually stored in the form of cash. Usually, black income is kept in the form of physical assets like gold, land, buildings etc. Hence the amount of black money countered by demonetization depend upon the amount of black money held in the form of cash and it will be smaller than expected.
 Impact on counterfeit currency: the real impact will be on counterfeit/fake currency as its circulation will be checked after this exercise.
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What is HVZ reaction?

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Ans.Treatment with bromine and a catalytic amount of phosphorus leads to the selective αbromination of carboxylic acids.
<h2>Mechanism of the HellVolhardZelinsky Reaction</h2>Phosphorus reacts with bromine to give phosphorus tribromide, and in the first step this converts the carboxylic acid into an acyl bromide.
An acyl bromide can readily exist in the enol form, and this tautomer is rapidly brominated at the αcarbon. The monobrominated compound is much less nucleophilic, so the reaction stops at this stage. This acyl intermediate compound can undergo bromide exchange with unreacted carboxylic acid via the anhydride, which allows the catalytic cycle to continue until the conversion is complete.
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The HVS (HellVolhardZelinsky) reaction is an organic reaction used to convert a carboxylic acid with an αhydrogen and a halogen, to an αhalo carboxylic acid, using a phosphorous catalyst and water.
The mechanism begins with the reaction of the carbonyl oxygen with phosphorous trihalide to form a P–O bond and release a halide anion. The halide then attacks the carbonyl to form an intermediate which rearranges to release an acyl chloride, an acid molecule, and a phosphine oxide.
The acyl chloride then tautomerizes to the enol form which subsequently attacks the halogen molecule to form an αhalo acyl halide. Water hydrolysis yields the final αhalo carboxylic acid product.
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What is linkage and recombination?

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Genetic linkage is the coupling of two genes' patterns of inheritance because they are located on the same chromosome.
Recombination is any of several processes by which genetic material ofdifferent origins becomes combined. It most commonly occursbetween two sets of parental chromosomes during production of germcells
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Ans.
Linkage is the tendency of alleles that are close together on a Chromosome to be inherited together during the meiosis phase of Sexual reproduction. Genes whose loci are nearer to each other are less likely to be separated onto different chromatids during Chromosomal crossover, and are therefore said to be genetically linked. In other words, the nearer two genes are on a chromosome, the lower is the chance of a swap occurring between them, and the more likely they are to be inherited together.
Recombination is the formation of new combinations of genes, either naturally, by crossing over or independent assortment, or in the laboratory by direct manipulation of genetic material.
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wha will be the effect of gst bill on PPC?

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The Goods And Services Tax (GST) will Effect the Ppc In both Long Run & Short Run . It is good for the long run as it will increase the production potential , gdp of country will also rise and ppc will shift rightward . In short run It will effect the ppc and it will shift leftward as the indirect tax’s will be removed and the supplier will decrease production
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what is menarch ?

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Ans. Menarch is the time in a girl's life when menstruation first begins. During the menarche period, menstruation may be irregular and unpredictable. Also known as female puberty.
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Why LiAlH4 is not reduce keton and NaBH4 is used

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Because it is stable compared to LiAlH4, it can be used in aqueous solutions and measured in open air where as LiAlH4 will react violently to moisture and water.
Sodium borohydride is a much less hazardous reagent than lithium aluminum hydride. The greater selectivity and safety of NaBH4 make it the preferred reagent in applications with Ketones.
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What is the differential equation of all non horizontal lines in a plane?

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Solution.
The general equation of all nonhorizontal lines in a plane is ax + by = c, where a ≠0
Differentiate w.r.t. y, We Get
adx/dy + b =0
again differentiate w.r.t. y
ad^{2}x/dy^{2} =0
=> d^{2}x/dy^{2}= 0
this is Required differential equation.
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Design a training programme for improvement of components of motor fitness.

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What is composition of charge in refining of copper from copper pyrite

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prove that the least perimeter of an isosceles triangle in which a circle of radius r can be inscribed is r.6(3)^1/2

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Ans.
ABC is an isosceles triangle with sides AB=AC. O is the center of circle of radius inscribed in the triangle. AD is the altitude,
So OD=OF=OE=r
So BD = CD ............. (1) ( altitude bisect the side)
BD = BE and CD = CF .............. (2) ( tangents from the same point are equal in length)
From (1) and (2)
BD=BE=CD=CF ........ (3)
Similariy AE = AF ........... (4) (tangents from the same point)
Perimeter of triangle (P) = AB + BC + AC
(P) = AE + EB + BD + CD + CF+AF
(P) = AE + AF + EB + BD + CD + CF
(P) = 2AE + 4BD (using 3 and 4)
In Right Triangle OEA,
$AE=\frac{OE}{Tanx}$
=> $AE=\frac{r}{\mathrm{tan}x}$
=> $AE=rcotx..............\left(5\right)$
In Right Triangle ABD
BD = AD*tanx
=> BD = (AO + OD)* tan x
=>$BD=\left(\frac{r}{\mathrm{sin}x}+r\right)\mathrm{tan}x$
=> $BD=rsecx+r\mathrm{tan}x...............\left(6\right)$
From 5 and 6
=> $\left(P\right)=2rcotx+4r(secx+\mathrm{tan}x)$
=> $\left(P\right)=r(2cotx+\hspace{0.17em}4secx+4\mathrm{tan}x)$
Differentiate w.r.t. x
we get
$\frac{dP}{dx}=r(2\mathrm{cos}e{c}^{2}x+4secx\mathrm{tan}x+4se{c}^{2}x)........\left(7\right)$
=> $\frac{dP}{dx}=r(\frac{2}{{\mathrm{sin}}^{2}x}+4\frac{\mathrm{sin}x}{{\mathrm{cos}}^{2}x}+\frac{4}{{\mathrm{cos}}^{2}x})$
To find critical value, Put $\frac{dP}{dx}=0$
=> $r(\frac{2}{{\mathrm{sin}}^{2}x}+4\frac{\mathrm{sin}x}{{\mathrm{cos}}^{2}x}+\frac{4}{{\mathrm{cos}}^{2}x})=0$
=> $(\frac{2}{{\mathrm{sin}}^{2}x}+4\frac{\mathrm{sin}x}{{\mathrm{cos}}^{2}x}+\frac{4}{{\mathrm{cos}}^{2}x})=0$
=> $\frac{2{\mathrm{cos}}^{2}x+4{\mathrm{sin}}^{3}x+4{\mathrm{sin}}^{2}x}{{\mathrm{sin}}^{2}x\times {\mathrm{cos}}^{2}x}=0$
=> $2(1{\mathrm{sin}}^{2}x)+4{\mathrm{sin}}^{3}x+4{\mathrm{sin}}^{2}x=0$
=> $2+2{\mathrm{sin}}^{2}x+4{\mathrm{sin}}^{3}x+4{\mathrm{sin}}^{2}x=0$
=> $2+4{\mathrm{sin}}^{3}x+6{\mathrm{sin}}^{2}x=0$
=>$2{\mathrm{sin}}^{3}x+3s{\mathrm{in}}^{2}x1=0$
=>$(2{\mathrm{sin}}^{3}x+2s{\mathrm{in}}^{2}x)+({\mathrm{sin}}^{2}x1)=0$
=>$2{\mathrm{sin}}^{2}x(\mathrm{sin}x+1)+(\mathrm{sin}x+1)(\mathrm{sin}x1)=0$
=> $(\mathrm{sin}x+1)(2{\mathrm{sin}}^{2}x+\mathrm{sin}x1)=0$
=> $(\mathrm{sin}x+1)=0or(2{\mathrm{sin}}^{2}x+\mathrm{sin}x1)=0$
=> $\mathrm{sin}x=1isnotpossiblebecausexcantbemorethan90\xb0so(2{\mathrm{sin}}^{2}x+\mathrm{sin}x1)=0$
=> $2{\mathrm{sin}}^{2}x+2\mathrm{sin}x\mathrm{sin}x1=0$
=> $2\mathrm{sin}x(\mathrm{sin}x+1)1(\mathrm{sin}x+1)=0$
=> $(2\mathrm{sin}x1)(\mathrm{sin}x+1)=0$
=> $(2\mathrm{sin}x1)=0or(\mathrm{sin}x+1)=0$
=> $\mathrm{sin}x=1isnotpossiblebecausexcantbemorethan90\xb0so(2\mathrm{sin}x1)=0$
=> $2\mathrm{sin}x1=0$
=> $\mathrm{sin}x=\frac{1}{2}$
=> $x=30\xb0$
at $\mathrm{sin}x=\frac{1}{2}$ sign changes from ve to +ve. so it is point of local minima, so at this point value ll be least.
Hence least perimeter is
$\left(P\right)=r(2cot30\xb0+\hspace{0.17em}4sec30\xb0+4\mathrm{tan}30\xb0)\phantom{\rule{0ex}{0ex}}$
=> $\left(P\right)=r(2\sqrt{3}+\hspace{0.17em}\frac{4\times 2}{\sqrt{3}}+4\frac{1}{\sqrt{3}})\phantom{\rule{0ex}{0ex}}$
=> $\left(P\right)=r\frac{\left(6+8+4\right)}{\sqrt{3}}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}$
=> $\left(P\right)=r\frac{18}{\sqrt{3}}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}$
=> $\left(P\right)=6\sqrt{3}r\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}$
Hence Proved
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Are the following topics added in 201617 syllabus??
1. Va de graft generator
2. Human eye
3. GPS (comm. System)

When will I receive my answer??
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These two (Va de graft generato Human eye) are not in syllabus but GPS (comm. System) is in syllabus.
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Explain development characteristics during childhood

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Whatbdo you mean by motor development

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Motor development means development of child's bones,muscles and ability to move around and manipulate his evnironment.
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Motor development refers to changes in children's ability to control their body's movements, from infants' first spontaneous waving and kicking movements to the adaptive control of reaching, locomotion, and complex sport skills.
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If A = 1 1 2 and B = 2 2 4
2 3 4 4 2 4
0 1 2 2 1 5
are two square matrix, find AB and hence solve the system of linear equation:
x  y = 3; 2x + 3y + 4z = 17; y + 2z = 7

It's A = 1 1 0
2 3 4
0 1 2
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From 1
We can say that
$X=\frac{1}{6}BC$
=> $X=\frac{1}{6}\left(\begin{array}{ccc}2& 2& 4\\ 4& 2& 4\\ 2& 1& 5\end{array}\right)\left(\begin{array}{c}3\\ 17\\ 7\end{array}\right)$
=> $X=\frac{1}{6}\left(\begin{array}{c}6+3428\\ 12+3428\\ 617+35\end{array}\right)$
=> $X=\frac{1}{6}\left(\begin{array}{c}12\\ 6\\ 24\end{array}\right)$
=>$X=\left(\begin{array}{c}2\\ 1\\ 4\end{array}\right)$
X = 2
y = 1
z = 4
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Ans.
$A=\left(\begin{array}{ccc}1& 1& 0\\ 2& 3& 4\\ 0& 1& 2\end{array}\right),B=\left(\begin{array}{ccc}2& 2& 4\\ 4& 2& 4\\ 2& 1& 5\end{array}\right)$
=> $AB\hspace{0.17em}=\left(\begin{array}{ccc}\left(2+4+0\right)& \left(220\right)& \left(4+4+0\right)\\ \left(412+8\right)& \left(4+64\right)& \left(812+20\right)\\ \left(04+4\right)& \left(0+22\right)& \left(04+10\right)\end{array}\right)$
=> $AB\hspace{0.17em}=\left(\begin{array}{ccc}6& 0& 0\\ 0& 6& 0\\ 0& 0& 6\end{array}\right)$
=> $AB=6IWhereIisidentitymatrix\phantom{\rule{0ex}{0ex}}$
=> ${A}^{1}=\frac{1}{6}B...........\left(1\right)$
x  y = 3
2x + 3y + 4z = 17
y + 2z = 7
We can represent these eqution In Matrix
$A=\left(\begin{array}{ccc}1& 1& 0\\ 2& 3& 4\\ 0& 1& 2\end{array}\right)$, $X=\left(\begin{array}{c}x\\ y\\ z\end{array}\right)$, $C=\left(\begin{array}{c}3\\ 17\\ 7\end{array}\right)$
=> $AX=C\phantom{\rule{0ex}{0ex}}=X={A}^{1}C$
From 1
=>
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Nominal GDP is Rs. 1200 and price index (with base 100) 120, calculate real GDP?

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Ans. Real GDP = Nominal GDP *100/Price Index
Put values
Real GDP = 1200*100/120
=> Real GDP = 1000
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Ans. We Know
Subsituting the given values,
=>
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Discuss the impact of different types of plating surface on athletes & the steps to overcome the impact by avoiding injuries.

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Personality and posture are two opposite sides of same coin. Comment.

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Nominal GDP can never be less than real GDP. Is it true or false giving reason.

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This is False Statement. Nominal GDP can be less than real GDP, if prices in the current year are less than the prices in the base yea
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Ans, False: Nominal GDP can be less than real GDP, if prices in the current year are less than the prices in the base year.
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A window is in the form of a rectangle surmounted by a semicircular opening. The total perimeter of the window is 30m. Find the dimension of the window so as to admit maximum light through the whole window

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Ans. Let 2r and x be the lenth and width of the window respectivily.
Then radius of semicircular portion is r.
Given : Perimeter of window = 10cm
=>
=>
Area of window is given by :
=>
=>
=>
=>
=>
Differentiate w.r.t r, we get
To Find critical point, Put
=>
=>
=>
=>
Therefore , by second derivative test, the area is the maximum when
Now length of window =
Width of Window x =
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A window is in the form of a rectangle surmounted by a semicircular opening. The whole perimeter of the window is 30m. Find the dimension of the window so as to admit maximum light through the whole window

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Ans. Let 2r and x be the lenth and width of the window respectivily.
Then radius of semicircular portion is r.
Given : Perimeter of window = 10cm
=>
=>
Area of window is given by :
=>
=>
=>
=>
=>
Differentiate w.r.t r, we get
To Find critical point, Put
=>
=>
=>
=>
Therefore , by second derivative test, the area is the maximum when
Now length of window =
Width of Window x =
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What do you mean by balanced diet?

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Balanced diet is the diet which contains variety of food and provide all the nutrients required for the body.Our body require all the nutrients such as vitamins,minerals, proteins, carbohydrates,fats,water and fibre also.
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Cu+ ion is unstable in aquous solution

Cu^{+} ion oxidizes and reduces simultaneously in aqueous solution to give Cu^{2+} and Cu^{+} ions. Therefore Cu^{+ }ion is unstable in aqueous solution and it disproportionates readily to Cu^{2+ }and Cu^{+ }Ions.
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Cu^{+} ion oxidizes and reduces simultaneously in aqueous solution to give Cu^{2+} and Cu^{+} ions. Therefore Cu^{+ }ion is unstable in aqueous solution and it disproportionates readily to Cu^{2+ }and Cu^{+ }Ions.
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In an aqueous medium, Cu2+ is more stable than Cu+. This is because although energy is required to remove one electron from Cu+ to Cu2+, high hydration energy of Cu2+ compensates for it. Therefore, Cu+ion in an aqueous solution is unstable. It disproportionates to give Cu2+ and Cu.
Stability in aqueous conditions depends on hydration energy of ions when they bond to molecules. Cu2+ ions has greater charge density than cu+ ions and hence forms much stronger bonds releasing more energy.
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Cu+ oxidises result in aqueous solution to Cu2+ and Cu. Cu2+ is more stable than Cu+ in aqueous solution as it has high hydration energy than Cu+.
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What is orthogonal vector

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In 2D or higherdimensional Euclidean space, two vectors are orthogonal if and only if their dot product is zero, i.e. they make an angle of 90°, or π/2 radians. Hence orthogonality of vectors is an extension of the concept of perpendicular vectors into higherdimensional spaces.
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Express the vector a^{›}=5i^{^} +2j^{^}+5k^{^} as the sum of two vectors such that one is parallel to vector b^{›}=3i^{^} +k^{^} and other is perpendicular to b^{›} .

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Given : $\stackrel{\rightharpoonup}{a}=5\hat{i}+2\hat{j}+5\hat{k},\stackrel{\rightharpoonup}{b}=3\hat{i}+\hat{k}$
Let Vector $\stackrel{\rightharpoonup}{a}=\stackrel{\rightharpoonup}{{a}_{1}}+\stackrel{\rightharpoonup}{{a}_{2}}$, Where $\stackrel{\rightharpoonup}{{a}_{1}}isparallelto\stackrel{\rightharpoonup}{b}and\stackrel{\rightharpoonup}{{a}_{2}}isperpendicularto\stackrel{\rightharpoonup}{b}$.
$as\stackrel{\rightharpoonup}{{a}_{1}}isparallelto\stackrel{\rightharpoonup}{b}\phantom{\rule{0ex}{0ex}}\stackrel{\rightharpoonup}{{a}_{1}}=\lambda (3\stackrel{\rightharpoonup}{i}+\stackrel{\rightharpoonup}{k})\phantom{\rule{0ex}{0ex}}=3\lambda \stackrel{\rightharpoonup}{i}+\lambda \stackrel{\rightharpoonup}{k}...................\left(1\right)$
Also
$\stackrel{\rightharpoonup}{a}=\stackrel{\rightharpoonup}{{a}_{1}}+\stackrel{\rightharpoonup}{{a}_{2}}$,
=> $\stackrel{\rightharpoonup}{{a}_{2}}=\stackrel{\rightharpoonup}{a}\stackrel{\rightharpoonup}{{a}_{1}}$,
=> $\stackrel{\rightharpoonup}{{a}_{2}}=5\stackrel{\rightharpoonup}{i}+2\stackrel{\rightharpoonup}{j}+5\stackrel{\rightharpoonup}{k}3\lambda \stackrel{\rightharpoonup}{i}\lambda \stackrel{\rightharpoonup}{k}$
=> $\stackrel{\rightharpoonup}{{a}_{2}}=(53\lambda )\stackrel{\rightharpoonup}{i}+2\stackrel{\rightharpoonup}{j}+(5\lambda )\stackrel{\rightharpoonup}{k}.................\left(2\right)$
As $\stackrel{\rightharpoonup}{{a}_{2}}isperpendicularto\stackrel{\rightharpoonup}{b}$
So, $\stackrel{\rightharpoonup}{{a}_{2}}\xb7\stackrel{\rightharpoonup}{b}=0$
$\left(\right(53\lambda )\stackrel{\rightharpoonup}{i}+2\stackrel{\rightharpoonup}{j}+(5\lambda \left)\stackrel{\rightharpoonup}{k}\right).(3\stackrel{\rightharpoonup}{i}+\stackrel{\rightharpoonup}{k})=0\phantom{\rule{0ex}{0ex}}=159\lambda +5\lambda =0\phantom{\rule{0ex}{0ex}}=10\lambda =20\phantom{\rule{0ex}{0ex}}=\lambda =2$
Put value of $\lambda $ in both equations.
$\stackrel{\rightharpoonup}{{a}_{1}}=6\stackrel{\rightharpoonup}{i}+2\stackrel{\rightharpoonup}{k}$
$\stackrel{\rightharpoonup}{{a}_{2}}=\stackrel{\rightharpoonup}{i}2\stackrel{\rightharpoonup}{j}+3\stackrel{\rightharpoonup}{k}$
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What is the treatment of "interest on short term borrowings" in cash flow statement

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The energy of a hydrogen atom in a ground state is 13.6 ev . then what is the k.E of electron in second excited state.
If electron jump from second excited state togramd state.t jen find wavelength of emitted radiation .

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