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What are the combinations of NOR & NAND gate

Posted by Aashka Shah (Apr 25, 2017 2:26 p.m.) (Question ID: 5033)

  • no , I am asking their combinations like

    2 NAND gate makes

    3 NAND gate makes which gate

    same as NOR

    2NOR , 3 NOR

    Posted by Aashka Shah (Apr 27, 2017 10:04 p.m.)
  • what their combinations are called

    Posted by Aashka Shah (Apr 25, 2017 5:50 p.m.)
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  • Answers:
  • They themselves are the combinations

    NOR GATE-OR GATE + NOT GATE

    NAND GATE- AND GATE + NOT GATE

    Answered by raghav aggarwal (Apr 27, 2017 1:26 p.m.)
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What is POYNTING VECTOR ?  &

What does it represent ?

Posted by Aashka Shah (Apr 24, 2017 11:46 p.m.) (Question ID: 5031)

  • Answers:
  • In physics, the Poynting vector represents the directional energy flux density (the rate of energy transfer per unit area) of an electromagnetic field. The SI unit of the Poynting vector is the watt per square metre (W/m2).

    The Poynting vector is defined as

    <dl> <dd></dd> </dl>

    where 

    • E is the electric field vector;
    • H is the magnetic field's auxiliary field vector.
    • S is Poynting vector
    Answered by Shweta Gulati (Apr 25, 2017 1:07 p.m.)
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When a wire of resistance R is streched and its radius becomes r/2 , then new resistance is ?

Posted by Aashka Shah (Apr 24, 2017 6:07 p.m.) (Question ID: 5026)

  • Answers:
  • Ans. Let the Initial Length of Wire = l

    Final length of Wire = L

    Intial Radius of wire = r

    FInal Radius of Wire r1 = {tex}r\over 2{/tex}

    So, Initial Volume of Wire = Final Volume of Wire

    {tex}=> \pi r^2 l = \pi r_1^2L{/tex}

    {tex}=> r^2 l = ({r\over 2})^2L{/tex}

    {tex}=> r^2 l = {r^2\over 4}L{/tex}

    {tex}=> L = 4l{/tex}

    Initial Area of Cross Section of wire (A) = {tex}\pi r^2{/tex} 

    Final area of Cross section of wire (A') = {tex}\pi r_1^2 = \pi{r^2\over 4}{/tex}

    Initial Resistance of Wire (R)= {tex}\rho {l\over A} = \rho {l\over \pi r^2}{/tex}

    Final Resistance of Wire (R') = {tex}\rho {L\over A'} = \rho {4l\over {\pi r^2\over 4}} ={ \rho 4\times 4l\over\pi r^2}{/tex}

    {tex}16\rho{l\over \pi r^2} = 16R{/tex}

    So new Resistance ll be 16 times of initial Resistance.

    Answered by Naveen Sharma (Apr 25, 2017 3:54 p.m.)
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Can there be a lower limit to the force acting between 2 equally charged particles saperated by the distance of 1 cm

Posted by khanak sharma (Apr 21, 2017 7:38 p.m.) (Question ID: 4985)

In  finding electric field due to thin plane sheet that area of cylinder is A then why we take it as area for lateral surfaces for which fluxes exists

 

Posted by Faizal Khan (Apr 20, 2017 7:53 p.m.) (Question ID: 4972)

Calculate the charge on alpha particle. Given charge on a proton = +1.6 × 10-19 C.

Posted by Ankita Singh (Apr 20, 2017 2:05 p.m.) (Question ID: 4970)

  • Answers:
  • An alpha particle is basically a Helium atom without electrons, and it consist two proton.

    Charge On 1 Proton = {tex}1.6\times 10^{-19}C{/tex}

    Charge on Alpha particle {tex}He^{+2} = 2\times 1.6\times 10^{-19}C = 3.2\times 10^{-19}C{/tex}

    Answered by Payal Singh (Apr 27, 2017 5:04 a.m.)
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How many electrons must be removed from a piece of metal to give it a positive charge of 1 × 10-7 C ?

Posted by Ankita Singh (Apr 20, 2017 2:04 p.m.) (Question ID: 4969)

  • Answers:
  • Let the number of electrons removed be n

    Charge on one electron = {tex} 1.6 \times 10^{-19} {/tex}

    Then

    {tex}=> n \times 1.6 \times 10^{-19} = 1\times 10^{-7}{/tex}

    {tex}=> n = {1\times 10^{-7} \over 1.6 \times 10^{-19} }{/tex}

    {tex}=> n = 6.25 \times 10^{11} {/tex}

     

    Answered by Payal Singh (Apr 22, 2017 11:38 a.m.)
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Calculate the total positive or negative charge on 3.11 g copper penny. Given Avogadro number = 6.02 × 1023 and atomic number of copper = 29 and atomic mass of copper = 63.5

 

Posted by Ankita Singh (Apr 20, 2017 2:02 p.m.) (Question ID: 4968)

Calculate the Charge on 26F56 nucleus.

Given the charge on proton = 1.6 × 10-19C.

(with process please solve it)

Posted by Ankita Singh (Apr 20, 2017 1:59 p.m.) (Question ID: 4967)

What is electric force?

 

Posted by Nrv Tech (Apr 20, 2017 7:30 a.m.) (Question ID: 4957)

  • Answers:
  • The attractive or repulsive interaction between any two charged objects is an ELECTRIC FORCE

    Answered by Aashka Shah (Apr 20, 2017 8:41 a.m.)
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What is an investigatory project? 

 

Posted by Aswathy S Madhav (Apr 19, 2017 8:56 p.m.) (Question ID: 4953)

  • Answers:
  • An investigatory project is basically any science experiment where you start with an issue or problem and conduct research or an investigation to decide what you think the outcome will be.

    Answered by Payal Singh (Apr 20, 2017 3 p.m.)
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Proof for relation between coulomb and stat coulomb

 

Posted by vijay pal singh pal (Apr 14, 2017 11:58 a.m.) (Question ID: 4877)

Two point charges +3AC and +8Ac repel each other with force of 40N If charge of -5uC is added to each of them, a then the force between them will becomes

Posted by Anant Batra (Apr 13, 2017 1:40 p.m.) (Question ID: 4864)

<a> </a>a particle is moving with constant speed v along x axis in positive direction. Find the angular velocity of the particle about the point (0,b) when the position of the particle is (a,0)

Posted by Paridhi Ruhela (Apr 13, 2017 1:16 a.m.) (Question ID: 4863)

why electric fields inside the conductor is zero

Thanks

 

Posted by Mohammad Aquib (Apr 11, 2017 11:30 a.m.) (Question ID: 4825)

  • Answers:
  • Because charge inside it is zero

    Answered by Pratit Luthra (Apr 11, 2017 6:19 p.m.)
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Sir if we know that any 2 like charges repel then why we need to prove that electric field doesn't cross over each other by drawing a tangent at a PT? 

Will the board give us marks if we explain the way above?

Posted by rakshak r gowda (Apr 10, 2017 11:57 p.m.) (Question ID: 4823)

 what is what is the electric flux offside once

Posted by manoj Sahoo (Apr 09, 2017 5:13 p.m.) (Question ID: 4796)

Define 1C  of charge

Posted by Ruhamah Thomas (Apr 04, 2017 8:16 p.m.) (Question ID: 4714)

  • Answers:
  • Ans. 1C of Charge is equal to the quantity of charge transferred in one second by a steady current of one ampere. It is equivalent to 6.2415 × 1018 elementary charges, where one elementary charge is the positive charge of a proton or the negative of the charge of an electron.

    Answered by Payal Singh (Apr 05, 2017 7:49 a.m.)
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What is electric dipole in case of equatorial line field?

 

Posted by Pal Purna (Apr 04, 2017 3:43 p.m.) (Question ID: 4710)

  • Answers:
  • Electric field due to an electric dipole at a point on the equatorial line is given as

    {tex}E = {1\over 4\pi \in_0} {p\over r^3}{/tex}

    The direction of electric dipole moment is from -q(negative charge) to +q(positive charge) and the resultant electric field at any point on equatorial line is in direction opposite to the electric dipole moment.

    Answered by Payal Singh (Apr 05, 2017 7:54 a.m.)
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Two similar charges Q are seperate by a certain distance a third q is placed between them are in such way that all the there charges are in equilibrium .find the magnitude from the other similar charge? 

Posted by SQUADRGON INSPIRALS (Apr 03, 2017 11:58 p.m.) (Question ID: 4700)

If a body contain odd electrons and another uncharged body is placed in contact with then no of electrons on first body will become?

 

Posted by yash shukla (Mar 31, 2017 11:35 p.m.) (Question ID: 4635)

  • Answers:
  • According to the symmetry and conservation of charge both the bodies will have equal amount of charge I.e. half...

     

    Answered by Priyankaa Singh (Apr 01, 2017 4:37 p.m.)
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why the direction of dipole is taken to be from -ve to +ve?

Posted by Vipin Kumar (Mar 31, 2017 12:21 p.m.) (Question ID: 4626)

  • Answers:
  • Ans. The torque on a dipole is given by,

    {tex}\overrightarrow \tau = \overrightarrow p + \overrightarrow E{/tex}

    The torque obtained is positive when the direction of the dipole is taken from negative charge to positive charge.

    Another reason is, in analogy with magnetic dipole where field outside the magnet is from North to South while field within the magnet is from South to North, the direction of electric dipole within the dipole is taken from negative charge to positive charge (this is just an analogy that is followed, in practical direction of electric lines of force is always from positive to negative charge).

    Answered by Naveen Sharma (Mar 31, 2017 2:34 p.m.)
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Distinguish between electrostatic and electric charge?

Posted by Sonu Joshi (Mar 31, 2017 11:52 a.m.) (Question ID: 4625)

  • Answers:
  • Ans.

    • Electrostatics is a branch of physics that deals with the phenomena and properties of stationary or slow-moving electric charges. Electric chare is study. 
    • Electric charge is the physical property of matter that causes it to experience a force when placed in an electromagnetic fiel. Electric chare is what we study in Electrostatic. 
    Answered by Naveen Sharma (Mar 31, 2017 2:37 p.m.)
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Is the exam paper of improvement is held with the compartment paper or it is separate ???

Posted by Vivek Rohilla (Mar 29, 2017 5:03 p.m.) (Question ID: 4593)

If i appear in the improvement exam of 2 subjects physics n math then my final marks given to me as a new marksheet or not

Posted by Vivek Rohilla (Mar 29, 2017 5 p.m.) (Question ID: 4592)

Distance of the centre of mass of a uniform cone from its vertex is z. If the radius of the cone is R and its height is h then find the value of z.

Posted by Soumili Biswas (Mar 28, 2017 8:35 a.m.) (Question ID: 4559)

Find the condition under which the charged particals moving with different speeds in the presence of electric and magnetic field vectors can be used to select charged particals of a particular speed.

Posted by Ramit Sindhu (Mar 26, 2017 9:25 a.m.) (Question ID: 4516)

A Person is running at a maximum speed of 4m/s to catch a train.When he is 6 metre away from the door of compartment,the train starts to leave at a constant acceleration of 1m/s .Find the time taken by person to catch train.

Posted by kokkula pardhav (Mar 23, 2017 3:19 p.m.) (Question ID: 4444)

  • Answers:
  • Ans. Let Train cover a distance d before man caught it in t time.

    So, Distance covered by man S = 6+d m

    Initial Speed of man u = 4m/s

    As man is running with constant speed, So a = 0

    Using

    {tex}S = ut +{1\over 2}at^2{/tex}

    {tex}=> 6+d = 4t +{1\over 2}\times 0\times t^2{/tex}

    {tex}=> 6+d = 4t +0{/tex}

    {tex}=> d = 4t -6 {/tex}………(1)

    Similarly initial Speed of Train u = 0

    acceleration a = 1m/s2

    Distance traveled = d

    So,

    {tex}=> d = 0\times t+{1\over 2}\times 1\times t^2{/tex}

    {tex}=> d ={ 1\over 2} t^2{/tex}………(2)

    From (1) & (2)

    {tex}=> 4t-6 = {1\over 2}t^2{/tex}

    {tex}=> 8t-12 = t^2{/tex}

    {tex}=>t^2- 8t+12 =0{/tex}

    On solving we get,

    t = 6s or 2s

    Answered by Naveen Sharma (Mar 23, 2017 5:16 p.m.)
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What is capacitance of a conductor? What is energy change if a conductor slab is inserted between the plate of capacitor?

Posted by Chandraprakash Chauhan (Mar 20, 2017 7:16 p.m.) (Question ID: 4231)

If a question is in parts,if answered in shuffled way marks will be deduced?

Posted by Arkadip jana (Mar 19, 2017 6:30 p.m.) (Question ID: 4140)

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