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Sayak Mondal 3 months ago
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Sayak Mondal 3 months ago
Few rules to keep homework help section safe, clean and informative.
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- Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
- Ask specific question which are clear and concise.
Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.
Sayak Mondal 3 months ago
Few rules to keep homework help section safe, clean and informative.
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- Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
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Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.
Sayak Mondal 3 months ago
Few rules to keep homework help section safe, clean and informative.
- Don't post personal information, mobile numbers and other details.
- Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
- Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
- Ask specific question which are clear and concise.
Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.
Sayak Mondal 3 months ago
Few rules to keep homework help section safe, clean and informative.
- Don't post personal information, mobile numbers and other details.
- Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
- Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
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Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.
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Posted by Tanushri Bhayani 1 year, 1 month ago
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Preeti Dabral 1 year, 1 month ago
The effective rate is the actual rate compounded annually. Therefore, the required sum S is given by
S = 12000 (1 + {tex}\frac{3}{100}{/tex})10 (1 + {tex}\frac{4}{100}{/tex})4 (1 + {tex}\frac{5}{100}{/tex})2
{tex}\Rightarrow{/tex} S = 12000 (1.03)10 (1.04)4 (1.05)2
{tex}\Rightarrow{/tex} S = 12000 (1.34391638) (1.16985856) (1.1025) = 20800.10
Hence, the amount is ₹20,800.10
Posted by Tanushri Bhayani 1 year, 2 months ago
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Posted by Tanushri Bhayani 1 year, 2 months ago
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Nishant Dogra 1 year, 2 months ago
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Posted by Tanushri Bhayani 1 year, 2 months ago
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Nishant Dogra 1 year, 2 months ago
Posted by Tanushri Bhayani 1 year, 2 months ago
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Tanushri Bhayani 1 year, 2 months ago
Posted by Tanushri Bhayani 1 year, 2 months ago
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Preeti Dabral 1 year, 2 months ago
Let the number of guests be x
If x > 100, then the amount received by the company will be-
{4800 - 200/10(x - 100)}x
Now, we need to maximize this amount so let us differentiate with respect to x as follows-
P = 4800x - 20(x - 100)x
P = 4800x - 20x² + 2000x
P = 6800x - 20x²
dP/dx = 6800 - 40x
differentiating again-
d²P/dx² = -40
As d²P/dx² > 0, the maximum value will occur at dP/dx = 0
⇒ 6800 - 40x = 0
40x = 6800
x = 6800/40
x = 170
Now, the amount received will be = 6800(170) - 20(170)²
= 1156000 - 578000
= 578000
Thus, the maximum amount that the company will receive is 5,78,000 when the number of guests are 170.
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Yash Jain 1 month, 3 weeks ago
1Thank You