Two charges of 2microC but opposite …
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Naveen Sharma 6 years, 11 months ago
Ans. Given :
Charge q = 2 mC = {tex}2 \times 10 ^{-6} C{/tex}
Distance b/w them (2a) = 10 cm = 10-1 m
Distance from mid-point on axial line r = 10 cm = 10-1 m
We Know
p = {tex}q \times 2a{/tex} = {tex}2 \times 10 ^{-6} \times 10^{-1} = 2 \times 10 ^{-7} {/tex}
Electric field due tp dipole on Axial line E = {tex}{1\over 4\pi \in } \times {2p\over r^2}{/tex}
= {tex}9\times 10 ^ 9 \times 2 \times 2 \times 10^{-7}\over 10^{-2} {/tex} = {tex}36 \times 10 ^ 7 \ N/C{/tex}
0Thank You