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Intrigate √tanx

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Intrigate √tanx

Posted by Akshat Mehta 6 years, 9 months ago

CBSE > Class 12 > Mathematics

2 answers

Payal Singh 6 years, 9 months ago

{tex}\int tan x. dx{/tex}

= {tex}\int{ sin x\over cos x} dx{/tex}

{tex}take \ cos\ x = t{/tex}

{tex}so\ sin \ x\ dx = -dt {/tex}

= {tex}\int-{1\over t} dt{/tex}

{tex}= - log\ t + c {/tex}

{tex}= - log (cos \ x)+ c {/tex}

= {tex}log |sec\ x| + c{/tex}

0Thank You

Sahdev Sharma 6 years, 9 months ago

{tex}\int tan x. dx{/tex}

= {tex}\int{ sin x\over cos x} dx{/tex}

Put cos x = t

Then

sin x dx = -dt

= {tex}-\int{1\over t} dt{/tex}

= - log t + c

= - log (cos x)+ c

= {tex}log |sec\ x| + c{/tex}

0Thank You

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Posted by Arpit Sahu 4 weeks, 2 days ago

CBSE > Class 12 > Mathematics

0 answers

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CBSE > Class 12 > Mathematics