A trader bought a number of …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Related Questions
Posted by Account Deleted 7 hours ago
- 0 answers
Posted by Siddharth Singh 1 day, 7 hours ago
- 0 answers
Posted by Rahul Rajput 7 hours ago
- 1 answers
Posted by Rajan Dubey 2 days, 9 hours ago
- 1 answers
Posted by Apeksha S 7 hours ago
- 0 answers
Posted by Somya Agrawal 7 hours ago
- 0 answers
Posted by Paru Devi Ninama Ninama 2 days, 14 hours ago
- 0 answers
Posted by Sandhya Vishwakarma 2 days, 13 hours ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sia ? 4 years, 10 months ago
Let number of articles he bought be x, and cost of each article be y.
Therefore, cost of x articles = xy = 900 {tex}\Rightarrow{/tex} y = {tex}\frac{900}{x}{/tex}
According to given information we have,
(x - 5)({tex}\frac{900}{x}{/tex} + 2) = 900 + 80
{tex}\Rightarrow{/tex}{tex}\frac { 900 x + 2 x ^ { 2 } - 4500 - 10 x } { x }{/tex} = 980
{tex}\Rightarrow{/tex} 2x2 + 890x - 4500 = 980x
{tex}\Rightarrow{/tex}2x2 - 90x- 4500 = 0
{tex}\Rightarrow{/tex}x2 - 45x - 2250 = 0
By factorization, we have,
D= b2-4ac
D= (-45)2 -4×1 (-2250)
D= 2025+ 9000
D=11025
x1 =-(-45)+105/2 , x2 = -(-45) -105/2
X1= 75, x2 =-75
since, the number of articles can not be negative,
So, x=75
{tex}\therefore{/tex} Number of articles = 75
0Thank You