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If an electron revolves in the path of a circle of radius of 0.5×10_10m at a frequency of 5×1015 cycles /s then find the electric current in the circle 

Posted by Gauri Kumari (Jul 23, 2017 11:01 p.m.) (Question ID: 6886)

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  • Current = Charge/Time

    Current on an electron = 1.6*10-19  C

    Frequency = 1/Time period

    5*1015 = 1/Time period

    Current = Charge*Frequency

    Current = 1.6*10-19*5*1011

                 = 8*10-8 ampere

    Answered by Jatin Kumar Yadav (Jul 24, 2017 1:36 a.m.)
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What is difference between permanent magnet and bar magnet

Posted by Mukul Kumar (Jul 23, 2017 7:40 p.m.) (Question ID: 6878)

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can you please solve the important questions part 3 in introduction of trignometry

Posted by Aditya Talwar (Jul 23, 2017 6:36 p.m.) (Question ID: 6877)

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  • which book....if possible write question

    Answered by Swami Jee (Jul 23, 2017 8:07 p.m.)
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How I will add 6 subjects in class10 when registration was done for five subjects in class 9 last year. How and when I can add six subjects in class ten and that is computer.

 

Posted by Viswajit India (Jul 23, 2017 4:40 p.m.) (Question ID: 6876)

  • you can consult your school before filling up the form. they can sure sort it out. Me too had 6th subject. but cant remember if registration was done in 5 or 6 subject.

    your school management will sure do it.

    Posted by Swami Jee (Jul 23, 2017 8:06 p.m.)
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  • you cannot add a 6th subject. a 6th subject can only be taken if a person is very bad at a particular subject and wishes to remove it from his/her curriculum.

    Answered by Aditya Talwar (Jul 23, 2017 6:39 p.m.)
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What is salt? How acids n base strength depends on h n oh ions????

What is water of crystalisation???

 

Posted by Himanshi Sharma (Jul 23, 2017 3:07 p.m.) (Question ID: 6873)

  • good question

    Posted by Jatin Kumar Yadav (Jul 23, 2017 3:41 p.m.)
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  • salt is a substance which is formed when acid reacts with base . It depends upon  pH( H and OH ions ) of relative acid and base

     

    Answered by Just Henry (Jul 24, 2017 12:20 a.m.)
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which sound does ali hear during his morning 'walk'? what do they convey?

Posted by Jot B (Jul 23, 2017 1:16 p.m.) (Question ID: 6871)

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What is power sharing 

Posted by Shraddha Ghogare (Jul 23, 2017 1:14 p.m.) (Question ID: 6870)

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  • you can use this definition :

    Power sharing is a term used to describe a system of governance in which all major segments of society are provided a permanent share ofpower; this system is often contrasted with government vs. opposition systems in which ruling coalitions rotate among various social groups over time.

    OR

    THIS ONE

    Power sharing is the distribution of power among the organs of the government like – legislature, executive and judiciary. It is an intelligent step to ensure the stability of political order. Besides, power sharing also includes sharing at the different levels like union, state and local level.

    Answered by Swami Jee (Jul 23, 2017 8:23 p.m.)
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What is mean by power sharing 

Posted by Shraddha Ghogare (Jul 23, 2017 1:13 p.m.) (Question ID: 6869)

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  • Power sharing is the distribution of power among the organs of the government like – legislature, executive and judiciary. It is an intelligent step to ensure the stability of political order. Besides, power sharing also includes sharing at the different levels like union, state and local level.

    Answered by Swami Jee (Jul 23, 2017 8:24 p.m.)
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fasttttttttttttt 'netaji ka chasma' par ak peom banaoooooooooooo.please(in 10-20 line)

Posted by Chitesh Sarve (Jul 23, 2017 10:53 a.m.) (Question ID: 6862)

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If SECa =X+1/4x, prove that SECa+ TANa =2x+1/2x

Posted by Mayank Mishra (Jul 22, 2017 9:55 p.m.) (Question ID: 6851)

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  • Given: {tex}\sec {\rm{A}} = x + {1 \over {4x}}{/tex}

    Then, {tex}\tan {\rm{A}} = \sqrt {{{\sec }^2}{\rm{A}} - 1} {/tex} 

    =>          {tex}\tan {\rm{A}} = \sqrt {{x^2} + {1 \over 2} + {1 \over {16{x^2}}} - 1} {/tex}

    =>          {tex}\tan {\rm{A}} = \sqrt {{{16{x^4} + 8{x^2} + 1 - 16{x^2}} \over {16{x^2}}}} {/tex}

    =>          {tex}\tan {\rm{A}} = \sqrt {{{16{x^4} - 8{x^2} + 1} \over {16{x^2}}}} {/tex}

    =>          {tex}\tan {\rm{A}} = \sqrt {{x^2} - {1 \over 2} + {1 \over {16{x^2}}}} {/tex}

    =>          {tex}\tan {\rm{A}} = \sqrt {{{\left( {x - {1 \over {4x}}} \right)}^2}} {/tex}

    =>          {tex}\tan {\rm{A}} = \pm \left( {x - {1 \over {4x}}} \right){/tex}

    Therefore, {tex}\sec {\rm{A}} + \tan {\rm{A}} = x + {1 \over {4x}} + x - {1 \over {4x}} = 2x{/tex}

    Or {tex}\sec {\rm{A}} + \tan {\rm{A}} = x + {1 \over {4x}} - x + {1 \over {4x}} = {1 \over {2x}}{/tex}

    Answered by Rashmi Bajpayee (Jul 23, 2017 4:48 p.m.)
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two metallic conductors Aand B are connected in series.Wire A has length'L' and radius R ,WHILE WIREaHAS LENGTH 2l and radius 2r. find the ratio of the total resistance of series combination and resistance of the wireA.if both the the wires are of same material

Posted by Ahmed Mousa (Jul 22, 2017 9:39 p.m.) (Question ID: 6849)

  • Please check if variables used are correct.

    Posted by Geetanjali Kunte (Jul 22, 2017 11:37 p.m.)
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Last year I was in class 9 and registration done for five subjects this year i am in class 10 how I will add my six  subjects that is computer

Posted by Viswajit India (Jul 22, 2017 8:35 p.m.) (Question ID: 6846)

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  • GO and ask your school in-charge before filling up the form....

    Answered by Swami Jee (Jul 23, 2017 8:38 p.m.)
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'netaji ka chasma' ke upar ak kavita banao please please (10-20 line)

fasttttttttt...............

Posted by Chitesh Sarve (Jul 22, 2017 8:28 p.m.) (Question ID: 6845)

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  • Netaji ka chashma gupta gupta me rajkot pass arya

    Maja sub ddekhaya

    Sub sun aya hahaha hahaha

     

    Answered by Harishmehta71@Gmail.Com Natvarlal (Jul 23, 2017 12:39 a.m.)
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I need important dates and events in histotry ch3 and ch5 class 10

Plzzz...

Posted by Aditya Rialch (Jul 22, 2017 8 p.m.) (Question ID: 6840)

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In an AP, the sum of first 10 terms is -150 and the sum of its next 10 terms is  -550.Find the arithmetic progression.

Posted by Anubhab Majumder (Jul 22, 2017 4:20 p.m.) (Question ID: 6834)

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  • in continuation from above 

    so AP is  3 , -1 , -5, -9, -13, -17 , -21, -25, -29, -33  

                                 sum of 1st 10 terms = -150

    -37 , -41, -45, -49, -53, - 57, -61, -65, -69, -73          

                                   sum of next 10 terms = - 550

    Answered by Hans Raj (Jul 22, 2017 8:06 p.m.)
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  • sorry due to power supply failure i could not complete

    from equation i and ii above we get

    2a + 9d = - 30

    2a + 19d = - 70

    - 10d = + 40

    d = - 4

    2a - 36 = - 30

    2a = 6

    a = 3

    Answered by Hans Raj (Jul 22, 2017 7:40 p.m.)
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  • Let first term = a

    common difference = d

    According to question,

    {tex}S_{10}= -150{/tex}

    {tex}=> {10\over 2}[2a+9d]=-150{/tex}

    {tex}=> 2a+9d= -30 \ ........(1){/tex}

    Also

    {tex}=> S_{20}-S_{10}=-550{/tex}

    {tex}=> S_{20}+150=-550{/tex}

    {tex}=> S_{20} = -700{/tex}

    {tex}=> {20\over 2}[2a+19d]=-700{/tex}

    {tex}2a+19d= -70\ .......(2){/tex}

    Solving (1) and (2)

    10 d = -40

    => d = -4

    => a = 3

    {tex}So AP = 3,-1,-5,-9,-13,.. {/tex}

    Answered by Sahdev Sharma (Jul 22, 2017 7:12 p.m.)
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  • Let a and d be the first term and common difference of A.P.

    {tex}S_{10}= -150{/tex}

    {tex}=> {10\over 2}[2a+9d]=-150{/tex}

    {tex}=> 2a+9d= -30 \ ........(1){/tex}

    Again

    {tex}a_{11}+a_{12}+......+a_{20}= -550{/tex}

    {tex}=> S_{20}-S_{10}=-550{/tex}

    {tex}=> S_{20}+150=-550{/tex}

    {tex}=> S_{20} = -700{/tex}

    {tex}=> {20\over 2}[2a+19d]=-700{/tex}

    {tex}2a+19d= -70\ .......(2){/tex}

    Subtract (1) from (2), we get

    10 d = -40

    => d = -4

    Putting value of d in (1) we get

    a = 3

    So AP = 3,-1,-5,-9,....

    Answered by Payal Singh (Jul 22, 2017 7:06 p.m.)
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  • sn = n/2 (2a + (n - 1)d)

     -150 = 5(2a + 9d)      - 30 = 2a + 9d ....... i

    - 550 + -150 = 10(2a +19d)

    - 700 = 10 (2a + 19d.....ii

    Answered by Hans Raj (Jul 22, 2017 7:05 p.m.)
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The sum of first q terms of an A.P. is 162.The ratio of its 6th term to its 13th term is 1:2.Find the first and 15th term of the A.P.

Posted by Anubhab Majumder (Jul 22, 2017 4:14 p.m.) (Question ID: 6833)

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  • The question is wrong. It  should be 9 in place of q

    <hr>

    Let first term of AP is a And Common difference is d.

    Given:

    {tex}a_6 = a+5d\\a_{13}=a+12d{/tex}

    {tex}{a_6\over a_{13}}={1\over 2}{/tex}

    {tex} =>{ a+5d\over a+12d}={1\over 2}{/tex}

    {tex}=> 2a+ 10 d = a+12d {/tex}

    {tex}=> a = 2d{/tex}

    Also, 

    {tex}S_9= {9\over 2}[2a+(9-1)d]{/tex}

    {tex}=> 162 = {9\over 2}(2a+8d){/tex}

    {tex}=> 36=[4d+8d]{/tex}

    {tex}=> d = 3 {/tex}

    Then a = 6

    {tex}a_{15}= 6+14\times 3 = 48{/tex}

    {tex}{/tex}

    Answered by Payal Singh (Jul 22, 2017 6:53 p.m.)
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  • The data is insufficient. The q should be replaced with 9.

    Let first term of AP = a

    Common difference = d

    {tex}a_6 = a+5d\\a_{13}=a+12d{/tex}

    According to question,

    {tex}{a_6\over a_{13}}={1\over 2}{/tex}

    {tex} =>{ a+5d\over a+12d}={1\over 2}{/tex}

    => 2a+ 10 d = a+12d

    => a = 2d ... (1)

    Also, 

    {tex}S_9=> 162= {9\over 2}[2a+8d]{/tex}

    {tex}=> 36=[4d+8d]{/tex}

    => d = 3

    So, a = 6

    {tex}a_{15}= 6+14\times 3 = 48{/tex}

    {tex}{/tex}

     

    Answered by Sahdev Sharma (Jul 22, 2017 6:49 p.m.)
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If one zero of the polynomial, (a⁴+4)x² + 13x + 4a, is reciprocal of the othe,Find ' a'

Posted by Gagan Sai (Jul 22, 2017 2:28 p.m.) (Question ID: 6831)

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  • Let one root = {tex}\alpha {/tex}

    Then second root = {tex}1\over \alpha{/tex}

    We know 

    Product of roots = {tex}c\over a{/tex}

    {tex}=> \alpha\times {1\over \alpha}= {4a\over a^2+4}{/tex}

    => {tex}a^2+4=4a{/tex}

    {tex}=> a^2-4a+4= 0{/tex}

    {tex}=> (a-2)^2= 0{/tex}

    => a-2= 0

    => a = 2

    Answered by Sahdev Sharma (Jul 22, 2017 2:50 p.m.)
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if x and y are two irrational nubers then tell whether x-y is always irrational or not?

Posted by Sona Shree (Jul 22, 2017 10:51 a.m.) (Question ID: 6826)

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  • It may be rational or irrational both.

    Answered by Sahdev Sharma (Jul 22, 2017 11:41 a.m.)
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what is the difference between  CaO and CaOH.

Posted by Gauri Misra (Jul 21, 2017 10:08 p.m.) (Question ID: 6823)

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  • CaO is Calcium Oxide, otherwise known as Quick Lime.

    CaOH is Calcium Hydroxide otherwise known as slaked lime which is obtained when calcium oxide is mixed or slaked with water.

    Answered by Sona Shree (Jul 22, 2017 10:54 a.m.)
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  • CaO is known as quick lime while Ca(OH)2     is slaked lime , aqueous form of slaked lime is known as lime water which is used to show the presence of CO2.

           

    Answered by Shridha Sharma (Jul 21, 2017 10:19 p.m.)
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fast........

Posted by Sudhakar Ubale (Jul 21, 2017 7:53 p.m.) (Question ID: 6817)

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what is reflex arc and what are it's components

Posted by Sudhakar Ubale (Jul 21, 2017 7:52 p.m.) (Question ID: 6816)

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  • The shortest possible route traversed by reflexaction is known as reflex arc. Components are receptor, sensory neuron, spinal cord, motor neuron and effector organ.

    Answered by Dr Pathikrt Banerjee (Jul 22, 2017 11:25 a.m.)
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Chemical reaction and equation

Posted by Sahil Wadhwa (Jul 20, 2017 9:55 p.m.) (Question ID: 6803)

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  • A chemical equation is the symbolic representation of a chemical reaction in the form of symbols and formulae, wherein the reactant entities are given on the left-hand side and the product entities on the right-hand side.

    Answered by Dr Pathikrt Banerjee (Jul 21, 2017 4:50 p.m.)
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which guide is best for maths,hindi,english,science,sst. please send list of best guide

Posted by Chitesh Sarve (Jul 20, 2017 9:55 p.m.) (Question ID: 6802)

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please create a poem on 'netaji ka chasma' in hindi.(in 10-20 line)

Posted by Chitesh Sarve (Jul 20, 2017 9:53 p.m.) (Question ID: 6801)

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 'netaji ka chasma' ke upar ak kavita banao please from book hindi.

Posted by Chitesh Sarve (Jul 20, 2017 9:50 p.m.) (Question ID: 6800)

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What lead to the clashers between the weaver and the gomasthas?

Posted by Vivek Yadav (Jul 20, 2017 8:50 p.m.) (Question ID: 6798)

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  • There were clashes between weavers & gomasthas because;

    1) The gomasthas were outsiders & had no social link with villages.

    2) a)They were arrogant.

    b) They marchedinto village with sepoys & peons.

    c) They punished weavers for delay in supply.

    3) The weavers could not sell their cloth to other buyers becuse they had to sell to the company due to the loans they took from them.

    4) They had to accept the price offered by the company to them, although it was very low.

    Answered by Sahdev Sharma (Jul 21, 2017 5:31 p.m.)
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Which hormone promotes senesensce  ???

Posted by Nikky Choudhary (Jul 20, 2017 8:50 p.m.) (Question ID: 6797)

  • Tell me fast plzzzz  !!!!

    Posted by Nikky Choudhary (Jul 20, 2017 8:55 p.m.)
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  • The hormones abscisic acid, ethylene, jasmonic acid and salicylic acid are accepted by most scientists as promoters of senescence, but at least one source lists gibberellins, brassinosteroids and strigolactones as also being involved.

    Answered by Sahdev Sharma (Jul 21, 2017 5:32 p.m.)
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  • Abscisic acidethylenejasmonic acid and salicylic acid are the main promoters of senescence.

    Answered by Akash Khetan (Jul 20, 2017 9:44 p.m.)
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What lead to the clashers betweentheweaverandthegomasthas?

Posted by Vivek Yadav (Jul 20, 2017 8:48 p.m.) (Question ID: 6796)

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  • There were clashes between weavers & gomasthas because;

    1) The gomasthas were outsiders & had no social link with villages.

    2) a)They were arrogant.

    b) They marchedinto village with sepoys & peons.

    c) They punished weavers for delay in supply.

    3) The weavers could not sell their cloth to other buyers becuse they had to sell to the company due to the loans they took from them.

    4) They had to accept the price offered by the company to them, although it was very low.

    Answered by Sahdev Sharma (Jul 21, 2017 5:33 p.m.)
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Formula of rust

Posted by We Are All Friends (Jul 20, 2017 8:47 p.m.) (Question ID: 6795)

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  • Fe2O3.xH2O where x is the no of water molecules

    Answered by Maziu Kikna (Jul 21, 2017 12:01 a.m.)
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  • Fe2O3.

    Answered by Kriti Bhawsar (Jul 20, 2017 9:03 p.m.)
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2/x^2-5/x+2=0

Bye using the method of compeleting the square.

Posted by Ananya Chaurasia (Jul 20, 2017 1:32 p.m.) (Question ID: 6788)

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  • {tex}{2\over x^2}{/tex}-{tex}{5\over x}{/tex}+2=0

    {tex}{2-5x+2x^2\over x^2}{/tex}=0

    2-5x+2x2=0

    2x2-5x+2=0 ------(1) 

    Now first of all we will make coefficient of x2 to 1

    So divide eq.(1) by 2 we get

    x2-{tex}{5\over 2}{/tex}x+1=0

    Now add and subtract the square of half of the coefficient of x we get

    x2-{tex}{5\over2}{/tex}x+{tex}({5\over 4})^2 -({5\over 4})^2{/tex}+1=0

    (x-{tex}{5\over 4})^2{/tex}-{tex}{25\over 16}{/tex}+1=0       [ by using identity (a-b)2=a2-2ab+b2]

    (x-{tex}{5\over 4})^2{/tex}-{tex}{25+16\over 16}{/tex}=0

    (x-{tex}{5\over 4})^2{/tex}-{tex}{9\over 16}{/tex}=0

    (x-{tex}{5\over 4})^2{/tex}={tex}{9\over 16}{/tex}

    (x-{tex}{5\over 4}{/tex})={tex}{\pm \sqrt{9 \over 16}}{/tex}

    (x-{tex}{5\over 4}){/tex}={tex}{\pm 3\over 4}{/tex}

    So x-{tex}{5\over 4}{/tex}={tex}{3\over 4}{/tex} or x-{tex}{5\over 4}{/tex}={tex}{-3\over 4}{/tex}

    x={tex}{3\over 4} +{5\over 4}{/tex}  or x={tex}{-3\over 4}+{5\over 4}{/tex}

    x={tex}{3+5\over 4}{/tex} or x={tex}{-3+5\over 4}{/tex}

    x={tex}{8\over 4}{/tex} or  x={tex}{2\over 4}{/tex}

    x=2 or x= {tex}{1\over 2}{/tex}

    Answered by Dharmendra Kumar (Jul 20, 2017 5:49 p.m.)
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  • {tex}2x^2-5x+2=0{/tex}

    {tex}=> (\sqrt 2x)^2-2\times \sqrt 2 \times {5\over 2\sqrt2}x+2 + ({5\over 2\sqrt 2})^2-({5\over 2\sqrt 2})^2=0{/tex}

    {tex}=> (\sqrt 2x)^2-2\times \sqrt 2 \times {5\over 2\sqrt2}x + ({5\over 2\sqrt 2})^2+2 -{25\over 8}=0{/tex}

    {tex}=> (\sqrt 2x)^2-2\times \sqrt 2 \times {5\over 2\sqrt2}x + ({5\over 2\sqrt 2})^2-{9\over 8}=0{/tex}

    {tex}=> (\sqrt 2x-{5\over 2\sqrt 2})^2-({3\over 2\sqrt 2})^2=0{/tex}

    {tex}=> (\sqrt 2x-{5\over 2\sqrt 2} +{3\over 2\sqrt 2})(\sqrt 2x-{5\over 2\sqrt 2} -{3\over 2\sqrt 2}){/tex}

    {tex}=> (\sqrt 2x-{1\over \sqrt 2} )(\sqrt 2x-{\sqrt 2}){/tex}

    Answered by Naveen Sharma (Jul 20, 2017 3:07 p.m.)
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