is_/3,_/6_/9_/12 form an a.p. ?? sir …
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Sia ? 4 years, 10 months ago
Common difference,
{tex}d_1 = \sqrt { 6 } - \sqrt { 3 }{/tex}
{tex}= \sqrt { 3 } ( \sqrt { 2 } - 1 ){/tex}
{tex}d_2= \sqrt { 9 } - \sqrt { 6 }{/tex}
{tex}= \sqrt { 3\times3 } - \sqrt{2\times 3}{/tex}
{tex}= 3 - \sqrt { 6 }{/tex}
{tex}d_3 = \sqrt { 12 } - \sqrt { 9 } {/tex}
{tex}= \sqrt { 4\times3 } - \sqrt { 9 } {/tex}
{tex}= 2 \sqrt { 3 } - 3{/tex}
As common difference does not equal.
Hence, The given series is not in A.P.
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