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The radius of the cirular ends …

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The radius of the cirular ends of a bucket of height 15cm are 14cm and rcm (r<14). If the volume of bucket is 5390cm*3 then the value of r.(π=22÷7)

Posted by Himesh Kaushik 7 years, 3 months ago

Bindu Agarwal 7 years, 3 months ago

V = $π ({r_{2}}^{2} - {r_{1}}^{2}) h$

5390 = 22/7(196-r²)15

196-r² = 114.33

r²= 196-114.33

r²=81.67

r = 9.03

ANSWER

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