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20 people (men,woman,children) earn 20 coins between them.Each man earns 3 coins,each woman earns 1-1/2 coins and each child earns 1/2 coin. How many men, women and children are there?

Posted by Aanvi Gupta (May 25, 2017 12:50 p.m.) (Question ID: 5482)

• Ans. let the number of men, women and children be denoted by M, W and C respectively.

Then

M + W + C = 20    ....... (1)

3M + 1.5 W + 0.5 C = 20  ........ (2)

Multiply equation (2) by (2)

6M + 3W + C = 40    ........(3)

From (1) and (2)

W + C = 20 - M ..........(4)

3 W + C = 40 - 6M     ...... (5)

The above equations will be solved for W and C in terms of M

W = 10 - {tex}{5M\over 2} {/tex}  and  C = 10  +  {tex} {3M\over 2}{/tex}

Because W and C have to be positive integers greater than 1 we conclude

(a) M is an even number.

(b) W {tex}\ge{/tex} 1 implies {tex}{5M\over 2 } \le 9{/tex}

it is seen W = 5 and C = 13 when M = 2 . Also {tex}{5M\over 2} = 5 \lt 9{/tex}

but When M is greater than 2 the condition is false . So

The only solution is M = 2, W =5 and C = 13

So Number of Men = 2

Number of Women = 5

Number of Children = 13

Answered by Naveen Sharma (May 25, 2017 4:25 p.m.)
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Solve:

{m-(m-1/2)}= {1-(m-2/3)}

Posted by Upakshi Dutta Baruah (May 18, 2017 7:41 p.m.) (Question ID: 5364)

• {tex}\{ m-(m-{1\over 2})\} = \{ 1-(m-{2\over 3})\}{/tex}

=> m - m + {tex}1\over 2{/tex}= 1 - m + {tex}2\over 3{/tex}

=> m = {tex}{5\over 3} - {1\over 2}{/tex}

=> m = {tex}7\over 6{/tex}

Answered by Payal Singh (May 18, 2017 9:11 p.m.)
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Solve :

3(5x-7)-2(9x-11)=4(8x-13)-17

Posted by Upakshi Dutta Baruah (May 16, 2017 11:13 a.m.) (Question ID: 5325)

• Thank you so much.

Posted by Upakshi Dutta Baruah (May 16, 2017 1:29 p.m.)
• Ans.
3(5x-7)-2(9x-11)=4(8x-13)-17

=> 15x - 21 - 18x + 22 = 32x - 52 - 17

=> 15x - 18x - 32x = - 52 - 17 + 21 - 22

=> -35x = - 70

=> x = {tex}{-70\over -35} = 2{/tex}

Answered by Naveen Sharma (May 16, 2017 12:49 p.m.)
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While three watchman were guarding an onchard,a thief slipped into and stole some apple. On this way out,he met the three watchman one after another and to each in turn he gave half the apples he had and two besides. In this way he managed to flee away with one apple. How many apples had he stolen originally?

Posted by Shalini Khandelwal (May 16, 2017 7:41 a.m.) (Question ID: 5323)

• Ans. let the number of apples he stole = x

Case 1 : Apples given to the first watchmen = {tex}{x\over 2} + 2 = {x+4\over 2}{/tex}

Apples remained  =  {tex}x - {x+4\over 2} = {2x-x-4\over 2} = {x-4\over 2}{/tex}

Case 1 :  Apples given to the second watchmen = {tex}{{x-4\over 2}\over 2} + 2 = {x-4\over 4} +2 {/tex}

{tex}= {x-4 + 8\over 4} = {x+4\over 4}{/tex}

Apples remained = {tex}{x-4\over 2} - {x+4\over 4} = {2x-8-x-4\over 4} = {x-12\over 4}{/tex}

Case 1 :  Apples given to third watchmen = {tex}{{x-12\over 4}\over 2} + 2 = {x-12\over 8}+2 {/tex}

{tex}= {x-12+16\over 8} = {x+4\over 8}{/tex}

Apples Remained = {tex}{x-12\over 4} -{x+4\over 8} = {2x-24-x-4\over 8} = {x-28\over 8}{/tex}

According to question :
{tex}{x-28\over 8} = 1 {/tex}

=> x - 28 = 8

=> x = 8+28

=> x = 36

So No of Apples he stole = 36

Answered by Naveen Sharma (May 16, 2017 9:05 a.m.)
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Two planes are flying towards each other and the difference between their speeds is 60km/have. If they are 2400km apart and passes each other after 5 hours,find their speeds.

Posted by Yash Thadani (May 07, 2017 7:43 p.m.) (Question ID: 5150)

• Let the speed of First plane is x km/hr and second plane is (x + 60) km/hr.

Time taken to pass each other = 5 hours.

Than, Distance covered by first plane in 5 hours = speed × time = x × 5 = 5x.

Distance covered by second plane in 5 hours = speed × time = (x + 60) 5 = 5x + 300

Distance coverec by first plane + distance covered by second plane = 2400 km

5x + (5x + 300) = 2400

10x + 300 = 2400

10x = 2400 - 300 = 2100

x = {tex}{{2100} \over {10}}\, = \,210{/tex}

Hence, the speed of first plane is = x = 210 km/hr

and the speed of second plane is = x + 60 = 210 + 60 = 270 km/hr

Answered by Rupender singh (May 08, 2017 7:41 a.m.)
Thanks (1)

The speed if boat in still water is 30 km/hr. it takes the same time for the boat to travel 5 km upstream and 10 km downstream find the speed of the stream.

Posted by Yash Thadani (May 07, 2017 12:02 a.m.) (Question ID: 5143)

• Let the speed of the stream be {tex}x{/tex} km/hr.

We know that, Speed = {tex}{{{\rm{Distance}}} \over {{\rm{Time}}}}{/tex}

Speed in upstream = (x -30) Km/h and Speed in downstream =(x + 30) Km/h

Then, Time = {tex}{{{\rm{Distance}}} \over {{\rm{Speed}}}}{/tex}

According to question,

{tex}{5 \over {x - 30}} = {{10} \over {x + 30}}{/tex}

=>          {tex}5\left( {x + 30} \right) = 10\left( {x - 30} \right){/tex}

=>          {tex}5x+150=10x-300{/tex}

=>          {tex}10x-5x=150+300{/tex}

=>          {tex}5x=450{/tex}

=>         {tex}x=90{/tex}

Therefore, the speed of stream is 90 km/hr

Answered by Rashmi Bajpayee (May 09, 2017 10:22 a.m.)
Thanks (2)

A boat travels 20 km upstream in a river in the same period of time as it takes to travel 30 km downstream if the rate of the stream is 4 km/hr find the speed of boat in still water.

Posted by Yash Thadani (May 06, 2017 10:57 a.m.) (Question ID: 5133)

• Ans. Let the speed of boat in still water = x Km/h

rate of stream = 4 Km/h

So, Speed of Boat downstream = (x+4) Km/h

Speed of Boat upstream = (x-3) Km/h

Time Taken to travel 20 Km Upstream = {tex}{20\over x-4 }\space hour {/tex}

Time Taken to travel 30 Km Downstream = {tex}{30\over x+4} \space hour{/tex}

ATQ,

{tex}=> {20\over x-4} = {30\over x+4}{/tex}

{tex}=> 20x+ 80 = 30x - 120{/tex}

{tex}=> 30x - 20x = 120 + 80 {/tex}

{tex}=> 10 x = 200 {/tex}

=> x = 20

Speed of Boat in still water = 20 Km/h

Answered by Naveen Sharma (May 06, 2017 4:51 p.m.)
Thanks (1)

A certain two digit number is equal to 9 times the sum of its digits.If 63 were subtracted from the number the digits would be reversed.Find the number.

Posted by priya Thadani (May 06, 2017 10:44 a.m.) (Question ID: 5132)

• Let the ones place digit be y and tens place be x, then the number be 10x + y.

According to quesiton,

10x + y = 9(x + y)

=>         10x + y = 9x + 9y

=>          10x - 9x = 9y - y

=>          x = 8y                               ..........(i)

Again according to second condition,

10x + y - 63 = 10y + x

=>          10 x - x + y - 10y = 63

=>          9x - 9y = 63

=>          x - y = 7

Putting the value of x from eq. (i), we get

8y - y = 7

=>         7y = 7

=>          y = 1

Putting the value of y in eq. (i), we get

x = 8 x 1 = 8

Therefore, the number is 10 x 8 + 1 = 81.

Answered by Rashmi Bajpayee (May 06, 2017 12:35 p.m.)
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Mayank visits  three shops one by one.At each shop,he spent two third of the money he had at that shop.If he is left with 32 with him after visiting the shop, find the amount of money he had in the beginning.

Posted by Yash Thadani (May 05, 2017 8:24 p.m.) (Question ID: 5126)

• Solution:

Let money he had in beginning = Rs. x

Money spend on first shop = {tex}2x\over 3{/tex}

Remaining Money = {tex}x - {2x\over 3} = {x \over 3}{/tex}

Money spend on 2nd shop = {tex} {2\over 3}\times {x \over 3} = {2x\over 9}{/tex}

Remaining Money = {tex}{x\over 3} - {2x\over 9} = {x \over 9}{/tex}

Money Spend on 3rd shop = {tex}{2\over 3} \times {x \over 9} = {2x\over 27}{/tex}

Remaining Money = {tex}{x \over 9}- {2x\over 27} = {x \over 27}{/tex}

ATQ,

=> {tex}{x\over 27} = 32{/tex}

=> x = 864

Answered by Payal Singh (May 06, 2017 7:44 a.m.)
Thanks (1)

Mahesh sells an article to David at aprofit of 8%, David sells it to mukesh at a loss of 5%.If Mukesh paid Rs 51700, how much did it cost to mahesh.

Posted by priya Thadani (May 05, 2017 4:31 p.m.) (Question ID: 5124)

• {tex}\eqalign{ & Let\,the\,C.P.\,ofarticle\,for\,Mahesh\,be\,Rs.\,100 \cr & \,the\,S.P.\,of\,article\,for\,Mahesh\,at\,8\% \,profit\, = \,Rs.\,(100\, + \,8)\, = \,Rs.\,108 \cr & Mahesh\,sells\,article\,to\,David\,at\,Rs.\,108 \cr & So,\,the\,C.P.\,ofarticle\,for\,David\,is\,Rs.\,108 \cr & Now,\,David\,sells\,the\,article\,to\,Mukesh\,at\,5\% \,loss. \cr & So,\,S.P.\,of\,article\,for\,David\,at\,5\% \,loss\, = \,\left( {{{100\, - \,loss\% } \over {100}}} \right)\, \times \,C.P.\, = \,\left( {{{100\, - \,5} \over {100}}} \right)\,108\, = \,{{95} \over {100}}\, \times \,108\, = \,Rs.\,102.60 \cr & It\,means\,Mukesh\,paid\,Rs.\,102.60\,to\,David. \cr & Now,\,C.P.\,of\,article\,for\,Mahesh\,is\,Rs.\,100,\,when\,Mukesh\,pays\,Rs.\,102.60\,to\,David. \cr & If\,Mukesh\,pays\,Rs.\,51700\,to\,David,\,than\,C.P.\,of\,article\,for\,Mahesh\,will\,be\, = \,{{51700\, \times \,\,100} \over {102.60}}\, = \,Rs.\,50389.86 \cr} {/tex}

Answered by Rupender singh (May 06, 2017 8:50 a.m.)
Thanks (1)

One third of a number increased by 5 is equal to its half part decreased by 5.find the number.

Posted by Yash Thadani (May 04, 2017 3:43 p.m.) (Question ID: 5112)

• Solution:

Let Number = x

ATQ,

{tex}{x\over 3} + 5={x\over 2} -5{/tex}

{tex}=> {x\over 3} - {x\over 2} = 5+5{/tex}

{tex}=> {3x-2x\over 6} = 10{/tex}

{tex}=> {x\over 6} = 10{/tex}

=> x = 60

Number  = 60

Answered by Payal Singh (May 04, 2017 7 p.m.)
Thanks (1)

The perimeter of a rectangular field is 84 meters .If the breadth of the field is increased by 2 meters and it's length is decreased by 4 meters ,the area is decreased by 32sq m.Find the length and breadth of the rectangular field.

Posted by Yash Thadani (May 03, 2017 2:37 p.m.) (Question ID: 5091)

• Ans. Perimeter of Field = 84 meter

Let Length of Field = x meter

Perimeter = {tex}2(x+breadth\space of \space field ){/tex}

=> {tex}84 = 2(x+breadth\space of \space field ){/tex}

{tex}=> 42 = x+breadth\space of \space field {/tex}

{tex}=> breadth\space of \space field = (42 - x ) meter{/tex}

Old Area = {tex}x\times (42-x) = 42x - x^2{/tex}

According to Ques,

New breadth = 42 - x + 2 = (44 - x) meter

New length  = (x - 4 ) meter

New Area = {tex}(44 - x) (x-4) = 44x - 176-x^2+4x {/tex}

So, New Area = Old Area - 32

=> {tex}44x - 176 -x^2 +4x = 42x-x^2 -32{/tex}

=> {tex}44x +4x - 42x -x^2 + x^2 = -32 + 176{/tex}

=> {tex}6x = 144{/tex}

=> x = 24

So, Length of Field = 24 meter

Breadth of Field = 42- 24 = 18 meter

Answered by Naveen Sharma (May 03, 2017 5:09 p.m.)
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Prabhat's age is one fourth of his father's age. Five years from now prabhat's age will be one third of his father's present age .Find their age.

Posted by Yash Thadani (May 02, 2017 3:41 p.m.) (Question ID: 5084)

• Ans. Let Present Age of Parbhat's Father = x

Then Present age of Parbhat = {tex}x\over 4{/tex}

Age of Prabhat after 5 years = {tex}{x\over 4 }+ 5 = {x+20\over 4}{/tex}

According to Ques,

=> {tex}{x+20\over 4} = {x\over 3}{/tex}

=> 3x + 60 = 4x

=> 4x - 3x = 60

=> x = 60

So, Present  Age of Father  = 60 years

Present age of Prabhat = {tex}{60\over 4 } = 15 {/tex} years

Answered by Naveen Sharma (May 02, 2017 4:37 p.m.)
Thanks (1)

Length of a rectangle is 6 cm more than its width.If it's length and breadth each is decreased by 3cm the area of new rectangle is decreased by 36 Sq cm.Find the original length and breadth of the original rectangle.

Posted by Yash Thadani (May 01, 2017 5:37 p.m.) (Question ID: 5071)

• Let the original Breadth of rectanlge be = x cm

and the original Length of rectangle be = (x + 6) cm

Therefore, Original Area = Length × Breadth = (x + 6) × x = x2 + 6x

Now, New Length = (x + 6) - 3 = x + 6 - 3 = x + 3

New Breadth = x - 3

Therefore, New Area = Length × Breadth = (x + 3) × (x - 3) = (x)2 - (3)2 = x2 - 9

According to Question

Original Area - New Area = 36 sq cm.

(x2 + 6x) - (x2 - 9) = 36

x2 + 6x - x2 + 9 = 36

6x + 9 = 36

6x = 36 - 9

6x = 27

x = {tex}{27\over6} = {9\over2}{/tex}

Hence, Original Length of Rectangle = x + 6 = {tex}{9\over 2} + 6 = {9 + 12\over 2} = {21\over 2} = 10.5{/tex}cm

Original Breadht of Rectangle = x = {tex}{9\over 2} = 4.5{/tex} cm

Answered by Rupender singh (May 02, 2017 9:56 a.m.)
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The sum of the digits of a two digit number is 14.If the number formed by reversing the digits is less than the original number by 18.Find the original numbers .

Posted by Yash Thadani (Apr 23, 2017 12:34 a.m.) (Question ID: 5001)

• Let x = the 10's digit
Let y = the units
:
10x + y = the original two digit number
:
The sum of the digits of a two-digit number is 14.
x + y = 14
:
"If the digits are reversed, the number is 18 less than the original number."
Rev no. = orig no. - 18
10y + x = 10x + y - 18
10y - y = 10x - x - 18
9y = 9x - 18
simplify, divide by 9
y = x - 2
:
In the sum equation replace y with (x-2)
x + (x-2) = 14
2x = 14 + 2
2x = 16
x = 8
obviously y = 6
:
86 is the original number
:
:
Check solution in the statement:
"If the digits are reversed, the number is 18 less than the original number."
68 = 86 - 18

Answered by Aashka Shah (Apr 23, 2017 7:48 a.m.)
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In a colony 6/8 of the total people were females.If the number of females is 36 more than that of the males ,how many males were there in the colony.

Posted by Yash Thadani (Apr 15, 2017 9:20 p.m.) (Question ID: 4894)

• Solution : let total number of people = x

Number of female = {tex}6x\over 8{/tex}

No of male = Total people - no of female

{tex}x - {6x \over 8} = {2x\over 8}{/tex}

According To Ques,

{tex}=> {6x\over 8} = 36 + {2x\over 8}{/tex}

{tex}=> {6x\over 8} - {2x\over 8} = 36{/tex}

{tex}=> {4x\over 8} = 36 {/tex}

=> x = 72

So No.of male = {tex}=> {2\over 8} \times 72 = 18{/tex}

Answered by Payal Singh (Apr 17, 2017 6:36 a.m.)
Thanks (1)

After travelling a distance of 32 4/5kmamera found tht she is still to cover 5/7 of the whole distance. What is the total distance covered by Amera?

Posted by Yash Thadani (Apr 12, 2017 5:34 p.m.) (Question ID: 4859)

• Let the total distance covered be x km.

Then according to question,

{tex}32{4 \over 5} + {5 \over 7}x = x{/tex}

=>     {tex}x - {5 \over 7}x = 32{4 \over 5}{/tex}

=>     {tex}{{7x - 5x} \over 7} = {{164} \over 5}{/tex}

=>     {tex}{{2x} \over 7} = {{164} \over 5}{/tex}

=>     {tex}x = {{164} \over 5} \times {7 \over 2}{/tex}

=>     {tex}x = {{1148} \over {10}}{/tex}= {tex}114{8 \over {10}}{/tex}km = 114.8 km

Answered by Rashmi Bajpayee (Apr 15, 2017 12:58 p.m.)
Thanks (1)

0.99999999........ Is a rational number or irrational number??

Posted by Sanjay Tiwari (Apr 11, 2017 8:55 p.m.) (Question ID: 4839)

• It can be written in the form of p/q where q is not 0

Posted by Akanksha Sinha (Apr 22, 2017 7:34 p.m.)
• It is a rational number.

Answered by Rupender singh (Apr 15, 2017 9:26 a.m.)
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0.999999999...........Is a rational number or irrational number ??

Posted by Sanjay Tiwari (Apr 11, 2017 8:55 p.m.) (Question ID: 4838)

• Rational no. Yes check itt

Answered by Arathi Naland (Apr 12, 2017 10:40 a.m.)
Thanks (1)

223223223+23453332

Posted by Sheetal 1978 (Apr 10, 2017 5:56 p.m.) (Question ID: 4812)

• 246676555

Answered by Vishanshu Rajak (Apr 10, 2017 7:04 p.m.)
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1/2+(-1/6)+(-2/3)+2/6 evaluate the following by grouping the rational no using the associative and communicative properties of addition

Posted by Sudha Rana (Apr 06, 2017 8:29 p.m.) (Question ID: 4747)

Posted by Sudha Rana (Apr 07, 2017 7:26 a.m.)
• {tex}{1 \over 2} + \left( {{{ - 1} \over 6}} \right) + \left( {{{ - 2} \over 3}} \right) + {2 \over 6}{/tex}

= {tex}{1 \over 2} - {1 \over 6} - {2 \over 3} + {2 \over 6}{/tex}

= {tex}{1 \over 2} - {2 \over 3} + \left( {{2 \over 6} - {1 \over 6}} \right){/tex}

= {tex}{1 \over 2} - {2 \over 3} + {1 \over 6}{/tex}

= {tex}{1 \over 2} + \left( {{1 \over 6} - {2 \over 3}} \right){/tex}

= {tex}{1 \over 2} + \left( {{{1 - 4} \over 6}} \right){/tex}

= {tex}{1 \over 2} - {3 \over 6}{/tex}

= {tex}{1 \over 2} - {1 \over 2}{/tex}

= 0

Answered by Rashmi Bajpayee (Apr 07, 2017 10:24 a.m.)
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I spent 5% of my total income in charity, 22% in buisness and 53% in family. Now i Had Rs. 2163 and forty paisa.  Find my total income

Posted by Senthil Nathan (Mar 23, 2017 7:31 p.m.) (Question ID: 4455)

• Total expenditure = 5% + 22% + 53% = 80%

Money left = 100% - 80% = 20%

Let total income be Rs. x.

According to question,

20% of x = 2163.40

20/100 × x = 2163.40

x = 2163.40 × 100 ÷ 20

x = Rs. 10817

Therefore total income is Rs. 10817.

Answered by Rashmi Bajpayee (Mar 24, 2017 4:49 p.m.)
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A person has deposited amount at 12% rate find out years to make principle double.

Posted by Rathi Kajal (Mar 21, 2017 9:06 a.m.) (Question ID: 4305)

• Let amount deposited be P. Then amount after required years will be 2P.

Now, S.I. = P x R x T / 100

S.I. = P x 12 x T / 100 = 2PT/25

Amount = P + S.I

2P = P + (2PT/25)

P = 2PT/25

2T = 25

T = 12.5

Therefore the time required for principal double is 12.5 years.

Answered by Rashmi Bajpayee (Mar 21, 2017 1:41 p.m.)
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At what rate ,  Rs 9900 amount to 13365 in 5 years

Posted by Rathi Kajal (Mar 20, 2017 11:23 p.m.) (Question ID: 4293)

• SI = (P X R X T )/100

P = Rs. 9900

A= Rs. 13,365

SI = A-P = Rs.3465

T = 5years

3465 X 100 = 9900 X R X 5

R = 7%

Answered by Shweta Gulati (Mar 21, 2017 1:12 a.m.)
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A cylindrical roller has perimeter 3.5 m and dimeter 2.8 m if roller rolled 200 times , find area of playground

Posted by Rathi Kajal (Mar 20, 2017 11:21 p.m.) (Question ID: 4292)

The cube of metal 3,4,5cm are melted and made in to single cube. Find the side of cube.

Posted by Rathi Kajal (Mar 20, 2017 11:19 p.m.) (Question ID: 4291)

• Volume of single cube = 33+43+53

a3 = 27+64+125

a3= 216

a3= 63

a=6cm

Answered by Shweta Gulati (Mar 21, 2017 1:15 a.m.)
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A person throw bucjet if water of square shape if total water is 8 litre  . Find out side of bucket.

Posted by Rathi Kajal (Mar 20, 2017 11:18 p.m.) (Question ID: 4290)

• Ans. Volume of water = 8 L = 0.008m3

Let Side of bucket = x m

Volume of bucket = Volume of water

=> x3 = 0.008

=> x3 = (0.2)3

=> x = 0.2 m  = 20 cm

Side of bucket is 20 cm

Answered by Naveen Sharma (Mar 21, 2017 7:38 a.m.)
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There are chikens with color 50 yellow 50 black and 50 red. Find inique probability of all colors.

Posted by Rathi Kajal (Mar 20, 2017 11:17 p.m.) (Question ID: 4289)

• Number of yellow chickens = 50

Number of black chickens = 50

Number of red chickens = 50

Total number of chickens = 50 + 50 + 50 = 150

Therefore, Probability of yellow colour chickens = {tex}{{50} \over {150}}\, = \,{1 \over 3}{/tex}

Probability of black colour chickens = {tex}{{50} \over {150}}\, = \,{1 \over 3}{/tex}

Probability of red colour chickens = {tex}{{50} \over {150}}\, = \,{1 \over 3}{/tex}

Answered by Rupender singh (May 03, 2017 8:28 a.m.)
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At what rate % per annum will rs 50000 to rs 86400 in 3 years if interest compounded annually

Posted by Rathi Kajal (Mar 20, 2017 11:15 p.m.) (Question ID: 4288)

• Ans. Amount (A)= 86400

Time(n) = 3 years

Principal (P)= 50000

Let rate (r) = r%

Then We Know,

{tex}A = P \times ({1 +{r\over 100}})^n{/tex}

{tex}=> 86400 = 50000\times ({1+{r\over 100}})^3{/tex}

{tex}=> {86400\over 50000} = ({1+{r\over 100}})^3{/tex}

{tex}=> {216\over 125} = ({1+{r\over 100}})^3{/tex}

{tex}=> ({6\over 5})^3= ({1+{r\over 100}})^3{/tex}

On comparing, We get

{tex}=> ({6\over 5})= ({1+{r\over 100}}){/tex}

{tex}=> {6\over 5} - 1= {r\over 100}{/tex}

{tex}=> {1\over 5} = {r\over 100} => r = 20\%{/tex}

Answered by Naveen Sharma (Mar 21, 2017 7:31 a.m.)
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Find compound interest on rs 25000 for 1 and half year at 20% rate compounded half yearly.

Posted by Rathi Kajal (Mar 20, 2017 11:13 p.m.) (Question ID: 4287)

• Principal = Rs. 25000

Time = {tex}1{1 \over 2}\,year{/tex} = 3 Half Years

Rate = 20% p.a. = 10% Half yearly.

{tex}Amount\,\, = \,\,P{\left( {1\,\, + \,\,{R \over {100}}} \right)^n}\,\, = \,\,25000\,{\left( {1\,\, + \,\,{{10} \over {100}}} \right)^3}\,\, = \,\,25000\,{\left( {1\, + \,{1 \over {10}}} \right)^3}\, = \,25000\,{\left( {{{10\, + \,1} \over {10}}} \right)^3}{/tex}

{tex}= \,25000\, \times \,\,{{11} \over {10}}\,\, \times \,\,{{11} \over {10}}\,\, \times \,\,{{11} \over {10}}\,\, = \,\,Rs. 33275{/tex}

Compound Interest = Amount - Principal = Rs (33275 - 25000) = Rs. 8275

Answered by Rupender singh (May 03, 2017 8:38 a.m.)
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