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N(n-1)(n-2)(n-3)(n-4)÷5=24

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N(n-1)(n-2)(n-3)(n-4)÷5=24
  • 2 answers

Aditya Sahu 4 months, 2 weeks ago

You can open and solve it but there is a trick n(n-1)(n-2)(n-3)(n-4) = 120 Now write 120 in multiples that are consecutive which are 1*2*3*4*5 so on comparing n=5

Harshit Malik ... 5 months, 3 weeks ago

Kon se Topic ka question h yeh 🧐
http://mycbseguide.com/examin8/

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